select * from dr_app_oper_log where create_time<=date'2023-06-23 23:45:00';
时间: 2024-04-10 20:29:32 浏览: 10
您好!我可以帮您解析这个SQL查询语句。根据您提供的语句,您想查询表 `dr_app_oper_log` 中 `create_time` 字段小于等于 `2023-06-23 23:45:00` 的所有记录。
请注意,这里的 `date'2023-06-23 23:45:00'` 是将日期字符串转换为日期类型的方式之一,具体取决于您使用的数据库系统。如果您的数据库系统不支持这种格式,您可以根据具体的系统进行调整。
如果您有任何其他问题,请随时提问!
相关问题
select RECIPE_DEPT_ID,RECIPE_DEPT_NAME,RECIPE_DOCT_ID,RECIPE_DOCT_NAME,EXECUTE_DEPT_ID,EXECUTE_DEPT_NAME,EXECUTE_DOCT_ID,EXECUTE_DOCT_NAME,ITEM_CLASS_ID,ITEM_CLASS_NAME,ITEM_ID,ITEM_NAME,ITEM_PRICE,SUM(AMOUNT)AMOUNT,SUM(COSTS)COSTS,TO_DATE('2023-05-01 00:00:00','YYYY-MM-DD HH24:MI:SS')OPER_TIME from I_OP_EXP_CHARGE_DETAIL where OPER_TIME between TO_DATE('2023-05-01 00:00:00','YYYY-MM-DD HH24:MI:SS') and TO_DATE('2023-05-31 23:59:59','YYYY-MM-DD HH24:MI:SS')and AMOUNT<>0 or COSTS <>0 GROPU BY RECIPE_DEPT_ID,RECIPE_DEPT_NAME,RECIPE_DOCT_ID,RECIPE_DOCT_NAME,EXECUTE_DEPT_ID,EXECUTE_DEPT_NAME,EXECUTE_DOCT_ID,EXECUTE_DOCT_NAME,ITEM_CLASS_ID,ITEM_CLASS_NAME,ITEM_ID,ITEM_NAME,ITEM_PRICE 这段代码报sql命令未正确结束,帮我看看什么原因
在你提供的查询代码中,存在一个错误:GROPU BY 应该是 GROUP BY。请改正这个拼写错误,将 "GROPU BY" 改为 "GROUP BY",即可解决问题。以下是已更正的代码示例:
```sql
SELECT
RECIPE_DEPT_ID, RECIPE_DEPT_NAME, RECIPE_DOCT_ID, RECIPE_DOCT_NAME,
EXECUTE_DEPT_ID, EXECUTE_DEPT_NAME, EXECUTE_DOCT_ID, EXECUTE_DOCT_NAME,
ITEM_CLASS_ID, ITEM_CLASS_NAME, ITEM_ID, ITEM_NAME, ITEM_PRICE,
SUM(AMOUNT) AS AMOUNT, SUM(COSTS) AS COSTS,
TO_DATE('2023-05-01 00:00:00', 'YYYY-MM-DD HH24:MI:SS') AS OPER_TIME
FROM
I_OP_EXP_CHARGE_DETAIL
WHERE
OPER_TIME BETWEEN TO_DATE('2023-05-01 00:00:00', 'YYYY-MM-DD HH24:MI:SS') AND TO_DATE('2023-05-31 23:59:59', 'YYYY-MM-DD HH24:MI:SS')
AND (AMOUNT <> 0 OR COSTS <> 0)
GROUP BY
RECIPE_DEPT_ID, RECIPE_DEPT_NAME, RECIPE_DOCT_ID, RECIPE_DOCT_NAME,
EXECUTE_DEPT_ID, EXECUTE_DEPT_NAME, EXECUTE_DOCT_ID, EXECUTE_DOCT_NAME,
ITEM_CLASS_ID, ITEM_CLASS_NAME, ITEM_ID, ITEM_NAME, ITEM_PRICE;
```
请注意,在上述示例中,我还添加了别名来标识聚合函数的结果(SUM(AMOUNT) AS AMOUNT, SUM(COSTS) AS COSTS)。这样可以更清晰地表示查询结果。如果还有其他问题,请随时提问。
SELECT matnr serge external _ number stat oper _ date oper _ time matnr serge oper message FROM INTO CORRESPONDING FIELDS OF TABLE lt _ tplnr _ dtl FOR ALL ENTRIES IN lt _ acct _ org WHERE external _ number = lt _ acct _ org - account _ number AND matnr ='1014000' OR matnr ='1016000' OR matrr = '1135000' OR matrnr ='1136000' OR stat E0006' GROUP BY external _ number matnr HAVING COUNT (*)=1. 这段代码 FOR ALL ENTRIES IN和HAVING COUNT (*) 冲突。如何修改
可以将代码改为以下形式来避免冲突:
SELECT matnr, serge, external_number, stat, oper_date, oper_time, oper_message
FROM lt_tplnr_dtl
WHERE external_number IN (lt_acct_org-account_number)
AND matnr IN ('1014000', '1016000', '1135000', '1136000')
AND stat = 'E0006'
GROUP BY external_number, matnr, serge, stat, oper_date, oper_time, oper_message
HAVING COUNT(DISTINCT external_number, matnr) = 1.
这个修改后的代码与原代码具有相同的功能,但避免了 ALL ENTRIES 和 COUNT(*) 冲突的问题。