一个代码梦到童年小游戏c++示例代码

当然可以。让我们来看一个简单的C++代码示例，模拟一个经典的童年游戏——"井字棋"（Tic Tac Toe），也称为“X's and O's”。这个程序实现了两个玩家轮流在3x3网格上放置他们的标记的游戏。

#include <iostream>
#include <vector>

// 代表游戏板的状态
enum class BoardState {
    Empty,
    PlayerOne,
    PlayerTwo
};

// 井字棋类
class TicTacToe {
private:
    std::vector<BoardState> board; // 3x3的游戏板

public:
    void print_board() const {
        for (int i = 0; i < 3; ++i) {
            for (int j = 0; j < 3; ++j) {
                char symbol;
                switch (board[i * 3 + j]) {
                    case BoardState.Empty:
                        symbol = ' ';
                        break;
                    case BoardState.PlayerOne:
                        symbol = 'X';
                        break;
                    case BoardState.PlayerTwo:
                        symbol = 'O';
                        break;
                }
                std::cout << symbol << " ";
            }
            std::cout << "\n";
        }
    }

    bool make_move(int row, int col, char player) {
        if (row < 0 || row >= 3 || col < 0 || col >= 3 || board[row * 3 + col] != BoardState.Empty) {
            return false;
        }
        board[row * 3 + col] = static_cast<BoardState>(player);
        return true;
    }

    // 其他方法...
};

int main() {
    TicTacToe game;
    game.print_board();
    while (!game.is_game_over()) { // 游戏结束条件...
        int row, col;
        std::cout << "Player X's turn, enter row and column: ";
        std::cin >> row >> col;
        game.make_move(row - 1, col - 1, 'X'); // 减一是因为索引从0开始

        game.print_board();
        // 判断并切换玩家...
    }
    return 0;
}