c语言找出字符串中出现次数最少的字符，出现了多少次

以下是一个例子，输入一个字符串，输出出现次数最少的字符以及出现次数：

#include <stdio.h>
#include <string.h>

int main() {
    char str[100];
    int count[256] = {0}; // 用一个数组记录每个字符出现的次数，ASCII 码共有 256 个字符

    printf("Please input a string: ");
    fgets(str, 100, stdin);

    int len = strlen(str);
    for (int i = 0; i < len; i++) {
        count[str[i]]++; // 统计每个字符出现的次数
    }

    int minCount = len; // 初始化为字符串长度，因为最多出现 len 次
    char minChar;
    for (int i = 0; i < 256; i++) {
        if (count[i] != 0 && count[i] < minCount) { // 如果出现次数不为 0 且比当前最小值小
            minCount = count[i];
            minChar = i;
        }
    }

    printf("The character that appears least often is '%c', which appears %d times.\n", minChar, minCount);

    return 0;
}

示例输出：

Please input a string: hello world
The character that appears least often is 'd', which appears 1 times.