Freertos用状态机写按键控制3个LED
时间: 2024-02-22 17:57:16 浏览: 164
好的,我可以为您提供一个简单的思路,您可以根据这个思路实现您的需求。
1. 首先需要定义三个LED的GPIO引脚和按键的GPIO引脚,以及它们的输入输出模式,可以使用FreeRTOS提供的GPIO驱动库。
2. 然后需要定义三个LED的状态,可以使用枚举类型或者宏定义,比如:
```c
#define LED_ON 1
#define LED_OFF 0
typedef enum {
LED1_STATE,
LED2_STATE,
LED3_STATE
} led_state_t;
```
3. 接着可以定义一个状态机,用于处理按键事件,比如:
```c
typedef enum {
IDLE_STATE,
PRESS_STATE,
RELEASE_STATE
} key_state_t;
key_state_t key_state = IDLE_STATE;
```
4. 然后在任务中循环检测按键状态,如果按键被按下,则将状态机切换到PRESS_STATE,如果按键被松开,则将状态机切换到RELEASE_STATE。
```c
void task_button(void *pvParameters)
{
gpio_config_t io_conf;
io_conf.intr_type = GPIO_INTR_ANYEDGE;
io_conf.mode = GPIO_MODE_INPUT;
io_conf.pin_bit_mask = (1ULL<<BUTTON_GPIO);
io_conf.pull_down_en = 0;
io_conf.pull_up_en = 1;
gpio_config(&io_conf);
uint32_t button_state = 0;
while(1) {
button_state = gpio_get_level(BUTTON_GPIO);
switch(key_state) {
case IDLE_STATE:
if (button_state == BUTTON_PRESSED) {
key_state = PRESS_STATE;
}
break;
case PRESS_STATE:
if (button_state == BUTTON_RELEASED) {
key_state = RELEASE_STATE;
}
break;
case RELEASE_STATE:
if (button_state == BUTTON_PRESSED) {
key_state = PRESS_STATE;
} else {
key_state = IDLE_STATE;
}
break;
default:
break;
}
vTaskDelay(10 / portTICK_PERIOD_MS);
}
}
```
5. 最后在任务中根据按键状态控制LED的状态,比如:
```c
void task_led(void *pvParameters)
{
led_state_t led_state[3] = {LED_OFF, LED_OFF, LED_OFF};
while(1) {
switch(key_state) {
case IDLE_STATE:
break;
case PRESS_STATE:
if (led_state[LED1_STATE] == LED_OFF) {
led_state[LED1_STATE] = LED_ON;
} else {
led_state[LED1_STATE] = LED_OFF;
}
break;
case RELEASE_STATE:
if (led_state[LED1_STATE] == LED_ON) {
led_state[LED2_STATE] = LED_ON;
} else {
led_state[LED2_STATE] = LED_OFF;
}
led_state[LED3_STATE] = LED_ON;
break;
default:
break;
}
gpio_set_level(LED1_GPIO, led_state[LED1_STATE]);
gpio_set_level(LED2_GPIO, led_state[LED2_STATE]);
gpio_set_level(LED3_GPIO, led_state[LED3_STATE]);
vTaskDelay(10 / portTICK_PERIOD_MS);
}
}
```
以上是一个简单的示例代码,您可以根据您的具体需求进行修改和优化。
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