写一个c++ 线程池
时间: 2023-07-06 21:38:37 浏览: 87
好的,以下是一个简单的 C++ 线程池的实现:
```cpp
#include <iostream>
#include <queue>
#include <thread>
#include <mutex>
#include <condition_variable>
#include <functional>
class ThreadPool {
public:
ThreadPool(size_t numThreads) {
for (size_t i = 0; i < numThreads; ++i) {
threads.emplace_back([this] {
while (true) {
std::function<void()> task;
{
std::unique_lock<std::mutex> lock(this->queueMutex);
this->condition.wait(lock, [this] {
return this->stop || !this->tasks.empty();
});
if (this->stop && this->tasks.empty()) {
return;
}
task = std::move(this->tasks.front());
this->tasks.pop();
}
task();
}
});
}
}
~ThreadPool() {
{
std::unique_lock<std::mutex> lock(queueMutex);
stop = true;
}
condition.notify_all();
for (std::thread& thread : threads) {
thread.join();
}
}
template<class F, class... Args>
void enqueue(F&& f, Args&&... args) {
auto task = std::make_shared<std::function<void()>>(std::bind(std::forward<F>(f), std::forward<Args>(args)...));
{
std::unique_lock<std::mutex> lock(queueMutex);
tasks.emplace([task] { (*task)(); });
}
condition.notify_one();
}
private:
std::vector<std::thread> threads;
std::queue<std::function<void()>> tasks;
std::mutex queueMutex;
std::condition_variable condition;
bool stop = false;
};
```
实现了一个简单的线程池,使用方法如下:
```cpp
void foo(int i) {
std::cout << "Hello from thread " << i << std::endl;
}
int main() {
ThreadPool pool(4);
for (int i = 0; i < 8; ++i) {
pool.enqueue(foo, i);
}
return 0;
}
```
这里创建了一个线程池,包含 4 个线程。然后循环了 8 次,将 foo 函数和循环变量 i 作为参数传递给线程池的 enqueue 函数,让线程池在空闲时执行这个函数。
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