写一个基于python的校园宿舍管理系统代码，不需要添加其他东西

好的，以下是一个简单的基于Python的校园宿舍管理系统代码：

# 宿舍管理系统

# 宿舍信息
dormitories = {
    "1号楼": {"101": "张三", "102": "李四", "103": "王五"},
    "2号楼": {"201": "赵六", "202": "钱七", "203": "孙八"},
    "3号楼": {"301": None, "302": None, "303": None}
}

# 显示所有宿舍信息
def show_dormitories():
    for building, rooms in dormitories.items():
        print(building)
        for room, student in rooms.items():
            print("  ", room, student)

# 添加学生
def add_student():
    building = input("请输入楼号：")
    room = input("请输入房间号：")
    if building not in dormitories:
        print("该楼号不存在")
        return
    if room not in dormitories[building]:
        print("该房间号不存在")
        return
    if dormitories[building][room] is not None:
        print("该房间已有人")
        return
    student_name = input("请输入学生姓名：")
    dormitories[building][room] = student_name
    print("添加成功")

# 删除学生
def remove_student():
    building = input("请输入楼号：")
    room = input("请输入房间号：")
    if building not in dormitories:
        print("该楼号不存在")
        return
    if room not in dormitories[building]:
        print("该房间号不存在")
        return
    if dormitories[building][room] is None:
        print("该房间没有人")
        return
    dormitories[building][room] = None
    print("删除成功")

# 主菜单
def main_menu():
    while True:
        print("1. 显示所有宿舍信息")
        print("2. 添加学生")
        print("3. 删除学生")
        print("4. 退出程序")
        choice = input("请输入你的选择：")
        if choice == "1":
            show_dormitories()
        elif choice == "2":
            add_student()
        elif choice == "3":
            remove_student()
        elif choice == "4":
            break
        else:
            print("无效的选择")

# 运行程序
main_menu()

以上代码实现了一个简单的校园宿舍管理系统，可以显示所有宿舍信息、添加学生、删除学生。你可以根据需要进行修改和扩展。