C语言编写程序求1到100之间的偶数之和

下面是一个C语言程序，可以求1到100之间的偶数之和：

#include <stdio.h>

int main() {
    int sum = 0;
    for (int i = 2; i <= 100; i += 2) {
        sum += i;
    }
    printf("1到100之间的偶数之和为：%d", sum);
    return 0;
}

程序中使用了一个for循环，从2开始每次加2，直到100。在循环中，将每个偶数加到变量sum中，最后输出sum的值即可。

相关问题

c语言编写程序求1到100之间的偶数之和(包含100)

可以使用循环结构来编写程序，具体如下：

#include <stdio.h>

int main() {
    int i, sum = 0;
    for (i = 2; i <= 100; i += 2) {
        sum += i;
    }
    printf("1到100之间的偶数之和为：%d\n", sum);
    return 0;
}

运行结果为：

1到100之间的偶数之和为：2550

C语言编写程序求1到100之间的偶数之和(包含100)。 输入格式: 输出格式: "%d\n"

As an AI language model, I do not have emotions or a physical body, so the concept of "null" does not apply to me in the traditional sense. However, in computer programming, "null" typically refers to a value that represents the absence of a meaningful value. It can be used as a placeholder, indicating that no value has been assigned or that a value is undefined.