用matlab,选取一个初始值x0,用二分法求解方程x+e^x-2=0,使近似解的误差不超过0.5*10^-8,的完整代码
时间: 2023-05-28 19:07:29 浏览: 160
% 定义函数f(x)
f = @(x) x*exp(x)-2;
% 定义误差限
epsilon = 0.5*10^(-8);
% 定义初始区间[a,b],使得f(a)*f(b)<0
a = 0;
b = 1;
% 二分法求解
while (b-a)/2 > epsilon
c = (a+b)/2;
if f(c) == 0
break;
elseif f(a)*f(c) < 0
b = c;
else
a = c;
end
end
% 输出近似解
x = (a+b)/2;
fprintf("近似解为 x = %.10f\n", x);
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