python使用scapy实现三次握手 四次挥手的代码

下面是使用 Scapy 实现 TCP 三次握手和四次挥手的示例代码：

TCP 三次握手：

from scapy.all import *

# 定义目标IP和端口
dst_ip = "192.168.1.1"
dst_port = 80

# 发送 SYN 请求
syn_packet = IP(dst=dst_ip)/TCP(dport=dst_port, flags="S")
syn_response = sr1(syn_packet, timeout=1)

# 发送 ACK 确认
if syn_response and syn_response.haslayer(TCP):
    if syn_response[TCP].flags & 2:
        ack_packet = IP(dst=dst_ip)/TCP(dport=dst_port, flags="A", ack=syn_response[TCP].seq + 1)
        send(ack_packet)
        print("TCP three-way handshake completed successfully!")
    else:
        print("SYN-ACK not received.")
else:
    print("No response to SYN.")

TCP 四次挥手：

from scapy.all import *

# 定义目标IP和端口
dst_ip = "192.168.1.1"
dst_port = 80

# 发送 FIN 请求
fin_packet = IP(dst=dst_ip)/TCP(dport=dst_port, flags="F")
fin_response = sr1(fin_packet, timeout=1)

# 发送 ACK 确认
if fin_response and fin_response.haslayer(TCP):
    if fin_response[TCP].flags & 2:
        ack_packet = IP(dst=dst_ip)/TCP(dport=dst_port, flags="A", ack=fin_response[TCP].seq + 1)
        send(ack_packet)

        # 发送第二个 FIN 请求
        fin2_packet = IP(dst=dst_ip)/TCP(dport=dst_port, flags="F")
        fin2_response = sr1(fin2_packet, timeout=1)

        # 发送 ACK 确认
        if fin2_response and fin2_response.haslayer(TCP):
            if fin2_response[TCP].flags & 2:
                ack2_packet = IP(dst=dst_ip)/TCP(dport=dst_port, flags="A", ack=fin2_response[TCP].seq + 1)
                send(ack2_packet)
                print("TCP four-way handshake completed successfully!")
            else:
                print("FIN-ACK2 not received.")
        else:
            print("No response to FIN2.")
    else:
        print("FIN-ACK not received.")
else:
    print("No response to FIN.")