用数据结构实现有头结点单链表逆置输入形式:第一行输入一个整数N；第二行输入N个整数，以空格作为分隔，创建单链表；输出形式:输出逆置后的单链表，元素之间以空格分隔。样例输入5 10 20 30 40 50样例输出50 40 30 20 10

以下是用 C 语言实现有头结点单链表逆置的代码：

#include <stdio.h>
#include <stdlib.h>

typedef struct Node {
    int data;
    struct Node *next;
} Node, *LinkedList;

LinkedList createLinkedList(int n) {
    LinkedList head = (LinkedList)malloc(sizeof(Node));
    head->next = NULL;
    Node *tail = head;
    for (int i = 0; i < n; i++) {
        int data;
        scanf("%d", &data);
        Node *node = (Node*)malloc(sizeof(Node));
        node->data = data;
        node->next = NULL;
        tail->next = node;
        tail = node;
    }
    return head;
}

void reverseLinkedList(LinkedList head) {
    Node *prev = NULL;
    Node *curr = head->next;
    while (curr != NULL) {
        Node *next = curr->next;
        curr->next = prev;
        prev = curr;
        curr = next;
    }
    head->next = prev;
}

void printLinkedList(LinkedList head) {
    Node *curr = head->next;
    while (curr != NULL) {
        printf("%d ", curr->data);
        curr = curr->next;
    }
    printf("\n");
}

int main() {
    int n;
    scanf("%d", &n);
    LinkedList list = createLinkedList(n);
    reverseLinkedList(list);
    printLinkedList(list);
    return 0;
}

如果输入样例为 "5 10 20 30 40 50"，则输出样例为 "50 40 30 20 10"。

希望这个回答能够帮到你！