学生类 - 属性：姓名、地址、年龄 测试类： - 使用TreeMap集合保存学生对象信息,要求创建不低于五个学生对象 - 集合添加元素时，要求以学生对象为键,住址为值 - TreeMap集合按照学生的年龄从大到小排序后，遍历集合并输出键值内容，输出格式不做要求

以下是Java代码实现：

import java.util.Map;
import java.util.TreeMap;

public class TestStudent {
    public static void main(String[] args) {
        Map<Student, String> map = new TreeMap<>((s1, s2) -> s2.getAge() - s1.getAge()); // 按照年龄从大到小排序
        map.put(new Student("Tom", "Beijing", 18), "Address1");
        map.put(new Student("Jerry", "Shanghai", 20), "Address2");
        map.put(new Student("Alice", "Guangzhou", 22), "Address3");
        map.put(new Student("Bob", "Shenzhen", 19), "Address4");
        map.put(new Student("Lucy", "Hangzhou", 21), "Address5");

        for (Map.Entry<Student, String> entry : map.entrySet()) {
            System.out.println(entry.getKey().toString() + " Address:" + entry.getValue());
        }
    }
}

class Student {
    private String name;
    private String address;
    private int age;

    public Student(String name, String address, int age) {
        this.name = name;
        this.address = address;
        this.age = age;
    }

    public String getName() {
        return name;
    }

    public String getAddress() {
        return address;
    }

    public int getAge() {
        return age;
    }

    @Override
    public String toString() {
        return "Student{" +
                "name='" + name + '\'' +
                ", address='" + address + '\'' +
                ", age=" + age +
                '}';
    }
}

输出结果为：

Student{name='Alice', address='Guangzhou', age=22} Address:Address3
Student{name='Lucy', address='Hangzhou', age=21} Address:Address5
Student{name='Jerry', address='Shanghai', age=20} Address:Address2
Student{name='Bob', address='Shenzhen', age=19} Address:Address4
Student{name='Tom', address='Beijing', age=18} Address:Address1