用c语言实现链表高精度减法
时间: 2023-10-25 12:10:31 浏览: 95
好的,我可以帮你解答如何用C语言实现链表高精度减法。高精度减法是指对于超过基本数据类型存储范围的大整数进行减法运算,需要使用链表等数据结构来存储和计算。具体实现方法可以参考以下步骤:
1. 定义一个结构体表示数字,结构体中包含一个指向下一位节点的指针和一个存储数字的int类型成员。
2. 创建两个链表来存储被减数和减数,输入这两个数,将它们从低位到高位依次插入到链表中。
3. 对两个链表同时进行遍历,从低位到高位开始执行减法运算。若被减数大于等于减数,则直接相减并将结果插入到新链表中;否则将高位借位,并减去借位后再进行相减。
4. 结果链表从高位到低位输出,若结果为0,则只输出一个0。
希望这个回答能帮助到你,如果有任何问题欢迎继续提问。
相关问题
动态链表存贮数据长整数、高精度运算c语言代码
以下是动态链表存储数据长整数、高精度运算的C语言代码示例:
```c
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
// 定义链表节点结构体
struct ListNode {
int val;
struct ListNode *next;
};
// 判断链表是否为空
int isListEmpty(struct ListNode *head) {
return head == NULL;
}
// 在链表尾部插入节点
void insertNode(struct ListNode **head, int val) {
struct ListNode *newNode = (struct ListNode*)malloc(sizeof(struct ListNode));
newNode->val = val;
newNode->next = NULL;
if (*head == NULL) {
*head = newNode;
return;
}
struct ListNode *cur = *head;
while (cur->next != NULL) {
cur = cur->next;
}
cur->next = newNode;
}
// 从字符串转换为链表
struct ListNode* listFromString(char *str) {
int len = strlen(str);
struct ListNode *head = NULL;
for (int i = len - 1; i >= 0; i--) {
int val = str[i] - '0';
insertNode(&head, val);
}
return head;
}
// 从链表转换为字符串
char* stringFromList(struct ListNode *head) {
char *str = (char*)malloc(sizeof(char) * 10000);
int index = 0;
while (head != NULL) {
str[index++] = head->val + '0';
head = head->next;
}
str[index] = '\0';
return str;
}
// 高精度加法
struct ListNode* add(struct ListNode* l1, struct ListNode* l2) {
struct ListNode *result = NULL;
int carry = 0;
while (l1 != NULL || l2 != NULL || carry != 0) {
int sum = carry;
if (l1 != NULL) {
sum += l1->val;
l1 = l1->next;
}
if (l2 != NULL) {
sum += l2->val;
l2 = l2->next;
}
carry = sum / 10;
sum %= 10;
insertNode(&result, sum);
}
return result;
}
// 高精度减法
struct ListNode* subtract(struct ListNode* l1, struct ListNode* l2) {
struct ListNode *result = NULL;
int borrow = 0;
while (l1 != NULL || l2 != NULL) {
int sub = borrow;
if (l1 != NULL) {
sub += l1->val;
l1 = l1->next;
}
if (l2 != NULL) {
sub -= l2->val;
l2 = l2->next;
}
if (sub < 0) {
sub += 10;
borrow = -1;
}
else {
borrow = 0;
}
insertNode(&result, sub);
}
while (!isListEmpty(result) && result->val == 0) {
struct ListNode *temp = result;
result = result->next;
free(temp);
}
return result;
}
// 高精度乘法
struct ListNode* multiply(struct ListNode* l1, struct ListNode* l2) {
struct ListNode *result = NULL;
struct ListNode *cur1 = l1;
while (cur1 != NULL) {
struct ListNode *cur2 = l2;
struct ListNode *temp = NULL;
int carry = 0;
while (cur2 != NULL || carry != 0) {
int mul = carry;
if (cur2 != NULL) {
mul += cur1->val * cur2->val;
cur2 = cur2->next;
}
carry = mul / 10;
mul %= 10;
insertNode(&temp, mul);
}
int zeros = 0;
while (zeros--) {
insertNode(&temp, 0);
}
result = add(result, temp);
cur1 = cur1->next;
}
return result;
}
// 高精度除法
struct ListNode* divide(struct ListNode* l1, struct ListNode* l2) {
struct ListNode *result = NULL;
struct ListNode *cur1 = l1;
while (cur1 != NULL) {
struct ListNode *temp = NULL;
int quotient = 0;
while (1) {
temp = multiply(l2, listFromString("0"));
for (int i = 0; i < quotient; i++) {
insertNode(&temp, 0);
}
if (cur1->val < stringFromList(temp)[0] - '0') {
break;
}
quotient++;
}
result = multiply(result, listFromString("10"));
insertNode(&result, quotient);
cur1 = cur1->next;
}
return result;
}
int main() {
char *str1 = "123456789";
char *str2 = "987654321";
struct ListNode *l1 = listFromString(str1);
struct ListNode *l2 = listFromString(str2);
struct ListNode *sum = add(l1, l2);
struct ListNode *diff = subtract(l1, l2);
struct ListNode *product = multiply(l1, l2);
struct ListNode *quotient = divide(l1, l2);
printf("Sum: %s\n", stringFromList(sum));
printf("Difference: %s\n", stringFromList(diff));
printf("Product: %s\n", stringFromList(product));
printf("Quotient: %s\n", stringFromList(quotient));
return 0;
}
```
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