def guess_key2(cipher_text, word1, word2 ,word3): letter_frequency = get_letter_frequency(cipher_text.lower()) excluded_letters = [letter for letter in letter_frequency.keys() if letter_frequency[letter] == 0] sorted_letters = sorted([letter for letter in letter_frequency.keys() if letter_frequency[letter] > 0], key=lambda x: letter_frequency[x], reverse=True) print("Excluded letters:", excluded_letters) print() most_common_letters_m = [sorted_letters[:1], sorted_letters[1:7], sorted_letters[7:10], sorted_letters[10:15], sorted_letters[15:20], sorted_letters[20:26]] # high 8 middle 8 low 10 f1 = ['e'] f2 = ['a', 'i', 'r', 't', 'o', 'n'] f3 = ['s', 'l', 'c'] f4 = ['u', 'p', 'm', 'd', 'h'] f5 = ['g', 'b', 'y', 'f', 'v'] mf = [f1, f2, f3, f4, f5] mp = [[j for j in range(len(mf[i]))] for i in range(len(mf))] flag = True while(flag): key = {} row_permutations = [itertools.permutations(row) for row in mp] matrix_permutations = itertools.product(*row_permutations) for permutation in matrix_permutations: for i in range(len(mp)): for j in range(len(mp[i])): key[most_common_letters_m[i][permutation[i][j]]] = mf[i][j] decrypted_text = decrypt(cipher_text, key) if is_plaintext(decrypted_text, word1, word2 ,word3): flag=False return key 这里每个key不包含全部的26组对应关系，请修改以将他们补齐

可以将代码修改为：

import itertools
import random

def guess_key2(cipher_text, word1, word2, word3):
    letter_frequency = get_letter_frequency(cipher_text.lower())
    excluded_letters = [letter for letter in letter_frequency.keys() if letter_frequency[letter] == 0]
    sorted_letters = sorted([letter for letter in letter_frequency.keys() if letter_frequency[letter] > 0], key=lambda x: letter_frequency[x], reverse=True)
    print("Excluded letters:", excluded_letters)
    print()
    most_common_letters_m = [sorted_letters[:1], sorted_letters[1:7], sorted_letters[7:10], sorted_letters[10:15], sorted_letters[15:20], sorted_letters[20:26]]
    # high 8 middle 8 low 10
    f1 = ['e']
    f2 = ['a', 'i', 'r', 't', 'o', 'n']
    f3 = ['s', 'l', 'c']
    f4 = ['u', 'p', 'm', 'd', 'h']
    f5 = ['g', 'b', 'y', 'f', 'v']
    mf = [f1, f2, f3, f4, f5]
    mp = [[j for j in range(len(mf[i]))] for i in range(len(mf))]
    flag = True
    while flag:
        key = {}
        row_permutations = [itertools.permutations(row) if len(row) > 1 else row for row in mp]
        matrix_permutations = itertools.product(*row_permutations)
        for permutation in matrix_permutations:
            for i in range(len(permutation)):
                if len(permutation[i]) == 1:
                    key[most_common_letters_m[i][0]] = mf[i][permutation[i][0]]
                else:
                    for j in range(len(permutation[i])):
                        key[most_common_letters_m[i][permutation[i][j]]] = mf[i][j]
            # 补齐未配对的字母
            remaining_letters = set('abcdefghijklmnopqrstuvwxyz') - set(key.keys())
            while len(remaining_letters) > 0:
                letter = random.sample(remaining_letters, 1)[0]
                value = random.sample(set('abcdefghijklmnopqrstuvwxyz') - set(key.values()), 1)[0]
                key[letter] = value
                remaining_letters = set('abcdefghijklmnopqrstuvwxyz') - set(key.keys())
            decrypted_text = decrypt(cipher_text, key)
            if is_plaintext(decrypted_text, word1, word2, word3):
                flag = False
                break
    return key

这样，我们在生成 key 的过程中，对于每个位置，如果对应的单词只包含一个字母，则直接将该字母和对应的字母配对，否则使用 permutations() 函数生成所有可能的排列，然后将排列中的字母按照顺序与 mf 中的字母配对。然后，我们使用随机字母补齐未配对的字母，直到 key 包含 26 对对应关系。最后，我们检查解密后的明文是否满足给定的单词列表，如果满足，则返回 key。

需要注意的是，这里的随机字母选择算法并不完美，如果 mf 中的字母和已配对的字母集合中的字母的交集不为空，可能会导致算法产生死循环。如果需要更安全和更合理的随机字母选择算法，可以参考 Python 标准库中的 secrets 模块。