Days Past Due 30+
时间: 2024-01-17 18:04:32 浏览: 18
Days past due 30 refers to a situation where a borrower has not made a payment on a loan or credit account for 30 days beyond the due date. This typically results in the lender or creditor issuing a late payment penalty and reporting the delinquent account to credit bureaus, which can negatively impact the borrower's credit score. If the account remains delinquent, further action may be taken by the lender or creditor, such as sending the account to a collections agency or pursuing legal action. It is important for borrowers to make timely payments to avoid delinquency and maintain good credit standing.
相关问题
for (int i = 0; i < days; i++, dfrist = dfrist.AddDays(1))
这段代码中存在语法错误,应该是将逗号改成分号:
```
for (int i = 0; i < days; i++, dfrist = dfrist.AddDays(1))
```
这个 `for` 循环用于迭代 `days` 天,并在每次迭代中将 `dfrist` 增加一天。其中,`i` 是循环计数器,`dfrist` 是一个 `DateTime` 类型的变量,`dfrist.AddDays(1)` 表示将 `dfrist` 增加一天后的新日期。
#include <stdio.h> #include <stdlib.h> struct Date { int year; int month; int day; }; int days(struct Date date) { int num = 0; int two = 0; if (date.year % 4 == 0) { if (date.year % 100 != 0) { two = 29; } else { two = 28; } if (date.year % 400 == 0) { two = 29; } } if (date.year % 400 == 0) { two = 29; } switch (date.month) { case 1: num = 0; break; case 2: num = 31; break; case 3: num = 31 + two; break; case 4: num = 31+31 + two; break; case 5: num = 30+ 31 + 31 + two; break; case 6: num = 31+ 30 + 31 + 31 + two; break; case 7: num = 30+ 31 + 30 + 31 + 31 + two; break; case 8: num = 31+ 30 + 31 + 30 + 31 + 31 + two; break; case 9: num = 31+ 31 + 30 + 31 + 30 + 31 + 31 + two; break; case 10:num = 30+ 31 + 31 + 30 + 31 + 30 + 31 + 31 + two; break; case 11: num = 31+ 30 + 31 + 31 + 30 + 31 + 30 + 31 + 31 + two; break; case 12: num = 30+ 31 + 30 + 31 + 31 + 30 + 31 + 30 + 31 + 31 + two; break; } return num + date.day; } int main() { struct Date a; scanf("%d%d%d", &a.year, &a.month, &a.day); printf("%d %d %d", a.year, a.month, a.day); printf("这一天是本年中的%d", cal(a)); system("pause"); return 0; }
这是一个计算给定日期是该年的第几天的程序。它首先定义了一个结构体Date表示日期,然后定义了一个函数days来计算输入的日期是该年的第几天。在days函数中,它使用了闰年的判断规则来计算二月份的天数,并通过switch语句来计算给定日期之前的所有天数。最后,它在main函数中读取输入的日期,并输出该日期及其在该年中的天数。