用python 画交叉三环

可以使用matplotlib库来画交叉三环，以下是示例代码：

import matplotlib.pyplot as plt

# 定义三个圆的中心点和半径
c1 = (0, 0)
r1 = 1
c2 = (1.5, 0)
r2 = 1
c3 = (0.75, 1.3)
r3 = 1

# 画三个圆
fig, ax = plt.subplots()
circle1 = plt.Circle(c1, r1, color='r', fill=False)
circle2 = plt.Circle(c2, r2, color='g', fill=False)
circle3 = plt.Circle(c3, r3, color='b', fill=False)
ax.add_artist(circle1)
ax.add_artist(circle2)
ax.add_artist(circle3)

# 画交叉部分
x1, y1 = c1
x2, y2 = c2
x3, y3 = c3
d1 = ((x2 - x1)**2 + (y2 - y1)**2)**0.5
d2 = ((x3 - x1)**2 + (y3 - y1)**2)**0.5
d3 = ((x3 - x2)**2 + (y3 - y2)**2)**0.5
theta1 = 2 * (r1**2 - r2**2 + d1**2) / (2 * d1**2)
theta2 = 2 * (r1**2 - r3**2 + d2**2) / (2 * d2**2)
theta3 = 2 * (r2**2 - r3**2 + d3**2) / (2 * d3**2)
p1x = x1 + (x2 - x1) * theta1 + (y2 - y1) * (theta1 * (theta1 - 1))**0.5
p1y = y1 + (y2 - y1) * theta1 + (x1 - x2) * (theta1 * (theta1 - 1))**0.5
p2x = x1 + (x2 - x1) * theta1 - (y2 - y1) * (theta1 * (theta1 - 1))**0.5
p2y = y1 + (y2 - y1) * theta1 - (x1 - x2) * (theta1 * (theta1 - 1))**0.5
p3x = x1 + (x3 - x1) * theta2 + (y3 - y1) * (theta2 * (theta2 - 1))**0.5
p3y = y1 + (y3 - y1) * theta2 + (x1 - x3) * (theta2 * (theta2 - 1))**0.5
p4x = x1 + (x3 - x1) * theta2 - (y3 - y1) * (theta2 * (theta2 - 1))**0.5
p4y = y1 + (y3 - y1) * theta2 - (x1 - x3) * (theta2 * (theta2 - 1))**0.5
p5x = x2 + (x3 - x2) * theta3 + (y3 - y2) * (theta3 * (theta3 - 1))**0.5
p5y = y2 + (y3 - y2) * theta3 + (x2 - x3) * (theta3 * (theta3 - 1))**0.5
p6x = x2 + (x3 - x2) * theta3 - (y3 - y2) * (theta3 * (theta3 - 1))**0.5
p6y = y2 + (y3 - y2) * theta3 - (x2 - x3) * (theta3 * (theta3 - 1))**0.5
plt.plot([p1x, p2x], [p1y, p2y], color='k')
plt.plot([p3x, p4x], [p3y, p4y], color='k')
plt.plot([p5x, p6x], [p5y, p6y], color='k')

# 设置坐标轴范围
ax.set_xlim(-2, 4)
ax.set_ylim(-2, 4)

# 显示图像
plt.show()

运行以上代码，即可得到交叉三环的图像。