如何用python解决

要用Python解决ZOJ2483这个计算几何问题，可以按照以下步骤进行：

1. 定义圆的类Circle，包含圆心坐标和半径信息，以及计算两个圆交点的方法intersect。

class Circle:
    def __init__(self, x, y, r):
        self.x = x
        self.y = y
        self.r = r
    
    def intersect(self, other):
        d = ((self.x - other.x) ** 2 + (self.y - other.y) ** 2) ** 0.5
        if d > self.r + other.r or d < abs(self.r - other.r):
            return None
        a = (self.r ** 2 - other.r ** 2 + d ** 2) / (2 * d)
        h = (self.r ** 2 - a ** 2) ** 0.5
        x2 = self.x + a * (other.x - self.x) / d
        y2 = self.y + a * (other.y - self.y) / d
        x3_1 = x2 + h * (other.y - self.y) / d
        x3_2 = x2 - h * (other.y - self.y) / d
        y3_1 = y2 - h * (other.x - self.x) / d
        y3_2 = y2 + h * (other.x - self.x) / d
        if x3_1 == x3_2 and y3_1 == y3_2:
            return (x3_1, y3_1)
        else:
            return [(x3_1, y3_1), (x3_2, y3_2)]

2. 读入输入数据，创建两个圆的对象。

x1, y1, r1 = map(float, input().split())
x2, y2, r2 = map(float, input().split())
c1 = Circle(x1, y1, r1)
c2 = Circle(x2, y2, r2)

3. 计算两个圆的交点，并判断是否有交点。

inter_points = c1.intersect(c2)
if inter_points is None:
    print(0)
    exit()

4. 计算交点构成的图形的面积。

if type(inter_points) == list:
    x1, y1 = inter_points[0]
    x2, y2 = inter_points[1]
    area = abs((x1 - x2) * (y1 - y2))
else:
    area = 0
print(round(area + c1.r ** 2 * math.acos((d ** 2 + r1 ** 2 - r2 ** 2) / (2 * d * r1)) + c2.r ** 2 * math.acos((d ** 2 + r2 ** 2 - r1 ** 2) / (2 * d * r2)) - 0.5 * ((-d + r1 + r2) * (d + r1 - r2) * (d - r1 + r2) * (d + r1 + r2)) ** 0.5, 2))

完整代码如下：