Set tree=JsonTreeUtil.getTree(menus, code, pcode, sort,name);

I'm sorry, as an AI language model, I do not have enough context to understand what programming language or framework you are using. Can you please provide more information and code snippets so I can assist you better?

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if (node.type === 'model' && node.id !== currentNodeKey.value) { return; } if (node.type !== 'model' && !keys?.includes(currentNodeKey.value)) { return; } if (node.type === 'model' && node.id === currentNodeKey.value) { currentNodeKey.value = ''; // 取消选中状态 getTree().setSelectedKeys([]); } if (node.type !== 'model' && keys?.includes(node.id)) { currentNodeKey.value = ''; } 简化代码

可以将这段代码进一步简化，去掉冗余的条件判断和重复的代码：

if (node.type === 'model') {
  if (node.id === currentNodeKey.value) {
    currentNodeKey.value = '';
    getTree().setSelectedKeys([]);
  }
  else {
    return;
  }
}
else {
  if (!keys?.includes(currentNodeKey.value)) {
    return;
  }
  else {
    currentNodeKey.value = '';
  }
}

这样就可以用更简洁的代码实现同样的功能。

if (node.type === 'script' && node.id !== currentScriptKey.value) { return; } // 删除主题和分类：当前选中节点不属于当前删除节点的子节点 if (node.type !== 'script' && !keys?.includes(currentScriptKey.value)) { return; } if (node.type === 'script' && node.id === currentScriptKey.value) { currentScriptKey.value = ''; // 取消选中状态 getTree().setSelectedKeys([]); } // 删除主题和分类：当前选中的脚本节点属于删除节点的子节点时，清空key if (node.type !== 'script' && keys?.includes(node.id)) { currentScriptKey.value = ''; }简化代码

以下是简化后的代码：

if (node.type === 'script') {
  if (node.id !== currentScriptKey.value) {
    return;
  } else {
    currentScriptKey.value = '';
    getTree().setSelectedKeys([]);
  }
} else {
  if (!keys?.includes(currentScriptKey.value)) {
    return;
  } else if (keys?.includes(node.id)) {
    currentScriptKey.value = '';
  }
}

简化后的代码主要是将原本分散在多个 if 语句中的逻辑整合在一起，同时简化了一些不必要的判断条件。