应该怎么样修改这个代码

可以将模板类C的构造函数参数改为T类型的引用，这样就可以接受传入的int类型参数了。修改后的代码如下：

#include <iostream>
using namespace std;

template <typename T>
class C {
public:
    C(T& a, T& b, T& c, T& d, T& e, T& f, T& g, T& h, T& m) {
        cc[0][0] = a; cc[0][1] = b; cc[0][2] = c;
        cc[1][0] = d; cc[1][1] = e; cc[1][2] = f;
        cc[2][0] = g; cc[2][1] = h; cc[2][2] = m;
    }

    C<T> operator+(const C<T>& c) {
        C<T> result(
            cc[0][0] + c.cc[0][0], cc[0][1] + c.cc[0][1], cc[0][2] + c.cc[0][2],
            cc[1][0] + c.cc[1][0], cc[1][1] + c.cc[1][1], cc[1][2] + c.cc[1][2],
            cc[2][0] + c.cc[2][0], cc[2][1] + c.cc[2][1], cc[2][2] + c.cc[2][2]
        );
        return result;
    }

    void get_num() {
        for (int i = 0; i < 3; i++) {
            for (int j = 0; j < 3; j++) {
                cout << cc[i][j] << " ";
            }
            cout << endl;
        }
    }

    // 友元函数重载减法运算符
    friend C<T> operator-(const C<T>& cc1, const C<T>& cc2) {
        C<T> result(
            cc1.cc[0][0] - cc2.cc[0][0], cc1.cc[0][1] - cc2.cc[0][1], cc1.cc[0][2] - cc2.cc[0][2],
            cc1.cc[1][0] - cc2.cc[1][0], cc1.cc[1][1] - cc2.cc[1][1], cc1.cc[1][2] - cc2.cc[1][2],
            cc1.cc[2][0] - cc2.cc[2][0], cc1.cc[2][1] - cc2.cc[2][1], cc1.cc[2][2] - cc2.cc[2][2]
        );
        return result;
    }

private:
    T cc[3][3];
};

int main() {
    int input[3][3];

    cout << "程序运行后结果:" << endl;

    for (int i = 0; i < 3; i++) {
        for (int j = 0; j < 3; j++) {
            cout << "输入第二个二维数组的值 (" << i << ", " << j << "): ";
            cin >> input[i][j];
        }
    }

    int a = 13, b = 34, c = 56, d = 23, e = 13, f = 134, g = 34, h = 34, m = 32;

    C<int> c_matrix(a, b, c, d, e, f, g, h, m);
    C<int> cc2_matrix(input[0][0], input[0][1], input[0][2],
                       input[1][0], input[1][1], input[1][2],
                       input[2][0], input[2][1], input[2][2]);

    C<int> result1 = c_matrix + cc2_matrix;
    cout << "相加后矩阵的值：" << endl;
    result1.get_num();

    C<int> result2 = c_matrix - cc2_matrix;
    cout << "相减后矩阵的值：" << endl;
    result2.get_num();

    return 0;
}

这样就可以通过编译了。