class Stack: def __init__(self): self.stack=[] def push(self,element): self.stack.append(element) def pop(self): if len(self.stack)>0: return self.stack.pop() def get_top(self): if len(self.stack)>0: return self.stack(-1) else : return None def is_empty(self): return len(self.stack)==0 def brace_match(s): match={')':'(',']':'[','}':'{'} stack=Stack() for ch in s: if ch in {'(','[','{'}: stack.push(ch) else: if stack.is_empty(): return False elif stack.get_top() == match[ch]: stack.pop() else: return False if stack.is_empty(): return True else: return False # match={')':'(',']':'[','}':'{'} # print(match[')']) print(brace_match('()'))

这段代码定义了一个栈(Stack)类，包括初始化方法(__init__)、入栈方法(push)、出栈方法(pop)、获取栈顶元素方法(get_top)和判断栈是否为空方法(is_empty)。同时还定义了一个括号匹配函数(brace_match)，该函数接受一个字符串参数s，遍历字符串中的每个字符，如果是左括号则入栈，如果是右括号则判断栈顶元素是否与其匹配，如果匹配则出栈，否则返回False。最后判断栈是否为空，如果为空则返回True，否则返回False。

相关问题

优化这段代码：class Stack: def __init__(self): self.stack=[] def push(self,element): self.stack.append(element) def pop(self): if len(self.stack)>0: return self.stack.pop() def get_top(self): if len(self.stack)>0: return self.stack(-1) else : return None def is_empty(self): return len(self.stack)==0 def brace_match(s): match={')':'(',']':'[','}':'{'} stack=Stack() for ch in s: if ch in {'(','[','{'}: stack.push(ch) else: if stack.is_empty(): return False elif stack.get_top() == match[ch]: stack.pop() else: return False if stack.is_empty(): return True else: return False # match={')':'(',']':'[','}':'{'} # print(match[')']) print(brace_match('()'))

优化后的代码如下：

class Stack:
def __init__(self):
self.stack = []

def push(self, element):
self.stack.append(element)

def pop(self):
if self.stack:
return self.stack.pop()

def get_top(self):
if self.stack:
return self.stack[-1]

def is_empty(self):
return not self.stack

def brace_match(s):
match = {')': '(', ']': '[', '}': '{'}
stack = Stack()
for ch in s:
if ch in {'(', '[', '{'}:
stack.push(ch)
else:
if stack.is_empty() or stack.get_top() != match[ch]:
return False
stack.pop()
return stack.is_empty()

• Design a Stack class (Eg 8 9 w) When the element pushed into the stack exceeds the capacity of the stack, it will throw a stack-full exception; When pop an element out of the stack when the stack is full, it will throw a stack-empty exception.

Sure, I can help you design a Stack class with the mentioned requirements. Here is a simple implementation of the Stack class in Python:

class Stack:
    def __init__(self, capacity):
        self.capacity = capacity
        self.stack = []

    def push(self, element):
        if len(self.stack) == self.capacity:
            raise Exception("Stack is full")
        self.stack.append(element)

    def pop(self):
        if len(self.stack) == 0:
            raise Exception("Stack is empty")
        return self.stack.pop()

    def is_empty(self):
        return len(self.stack) == 0

    def is_full(self):
        return len(self.stack) == self.capacity

In the constructor, we set the capacity of the stack and initialize an empty list to store the elements. The `push` method adds an element to the stack but raises an exception if the stack is full. The `pop` method removes and returns the top element from the stack but raises an exception if the stack is empty. The `is_empty` and `is_full` methods return True or False depending on whether the stack is empty or full.