0-1背包问题java代码

以下是一个简单的0-1背包问题的Java代码：

public class KnapsackProblem {
    public static int knapsack(int[] weights, int[] values, int capacity) {
        int n = weights.length;
        int[][] dp = new int[n + 1][capacity + 1];
        for (int i = 1; i <= n; i++) {
            for (int j = 1; j <= capacity; j++) {
                if (weights[i - 1] <= j) {
                    dp[i][j] = Math.max(dp[i - 1][j], dp[i - 1][j - weights[i - 1]] + values[i - 1]);
                } else {
                    dp[i][j] = dp[i - 1][j];
                }
            }
        }
        return dp[n][capacity];
    }

    public static void main(String[] args) {
        int[] weights = {10, 20, 30};
        int[] values = {60, 100, 120};
        int capacity = 50;
        System.out.println(knapsack(weights, values, capacity));
    }
}

该代码使用动态规划的思想解决了0-1背包问题，时间复杂度为O(N*W)，其中N是物品数量，W是背包容量。