在map_huiyan_short_stay和map_huiyan_long_stay_with_area两个表中,取表1满足查询条件2>x>1的cuid与表2的cityname通过join对接,记录并输出每个cityname相同的数量
时间: 2024-04-07 17:33:03 浏览: 51
可以使用以下SQL语句来实现你的需求:
```sql
SELECT table2.cityname, COUNT(*) as count
FROM table1
JOIN table2 ON table1.cuid = table2.cuid
WHERE table1.x > 1 AND table1.x < 2
GROUP BY table2.cityname;
```
请将上述语句中的 "table1" 替换为 "map_huiyan_short_stay",将 "table2" 替换为 "map_huiyan_long_stay_with_area",然后执行该SQL语句即可获取每个城市名称相同的记录数量。
相关问题
hive在map_huiyan_short_stay和map_huiyan_long_stay_with_area两个表中,取表1满足查询条件2>x>1的cuid与表2的cityname通过join对接,记录并输出每个cityname相同的数量
在Hive中,你可以使用以下HQL语句来实现你的需求:
```sql
SELECT table2.cityname, COUNT(*) as count
FROM map_huiyan_short_stay table1
JOIN map_huiyan_long_stay_with_area table2 ON table1.cuid = table2.cuid
WHERE table1.x > 1 AND table1.x < 2
GROUP BY table2.cityname;
```
请将上述语句中的 "map_huiyan_short_stay" 替换为你的第一个表名,将 "map_huiyan_long_stay_with_area" 替换为你的第二个表名,然后执行该HQL语句即可获取每个城市名称相同的记录数量。
检查一下是否存在语法错误insert overwrite local directory '/home/map/chenlinyu/task2' row format delimited fields terminated by '\t' SELECT t2.city_name, COUNT(*) as count FROM map_huiyan_short_stay t1 JOIN map_huiyan_long_stay_with_area t2 ON t1.cuid = t2.cuid WHERE t2.event_day=20230605 and t1.loc_x>12993523 and t1.loc_x<13012467 and t1.loc_y>4773079 and t1.loc_y<4789463 group by t2.city_name
这段代码存在一些语法错误。在使用INSERT OVERWRITE语句时,需要指定目标表,而你的代码中没有指定目标表。此外,你还需要使用INSERT语句来将查询结果插入到指定的目录中。
以下是修正后的代码:
```sql
INSERT OVERWRITE DIRECTORY '/home/map/chenlinyu/task2'
ROW FORMAT DELIMITED
FIELDS TERMINATED BY '\t'
SELECT t2.city_name, COUNT(*) AS count
FROM map_huiyan_short_stay t1
JOIN map_huiyan_long_stay_with_area t2 ON t1.cuid = t2.cuid
WHERE t2.event_day = 20230605
AND t1.loc_x > 12993523
AND t1.loc_x < 13012467
AND t1.loc_y > 4773079
AND t1.loc_y < 4789463
GROUP BY t2.city_name;
```
请确保将目标表替换为你想要插入数据的实际目录,并执行修正后的代码。
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