char a[5],*p=a;p=“ABCD”
时间: 2024-05-15 22:19:29 浏览: 12
这段代码有问题,不能将字符串直接赋值给指向字符数组的指针。
应该这样写:
```c++
char a[5], *p = a;
strcpy(a, "ABCD"); // 将字符串复制到字符数组中
```
或者这样写:
```c++
char a[5] = "ABCD", *p = a;
```
这两种写法都可以将字符串赋值给字符数组,并将指针指向该数组的首地址。
相关问题
char a[5],*p=a; *p="abcd"
This code will result in a compilation error.
Explanation:
- `char a[5]` creates an array of 5 characters.
- `*p=a` assigns the address of the first element of the array `a` to the pointer variable `p`.
- `*p="abcd"` tries to assign a string literal "abcd" to the memory location pointed to by `p`, which is not allowed because `p` points to a single character and not a string.
To assign the string "abcd" to the array `a`, we can use the `strcpy()` function like this:
```c
char a[5], *p=a;
strcpy(p, "abcd");
```
This will copy the string "abcd" to the array `a` starting at the memory location pointed to by `p`.
char a[5],*p=a;a=“ABCD”
This code will not compile because you cannot assign a string literal to an array in C.
Additionally, you cannot reassign the address of an array, so the statement `a = "ABCD"` is invalid.
If you want to initialize an array with a string literal, you can use the `strcpy` function from the string.h library:
```
#include <string.h>
char a[5], *p = a;
strcpy(a, "ABCD");
```
This will copy the characters in the string literal "ABCD" to the array `a`. The pointer `p` is also initialized to point to the first element of `a`.
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