优化成MYSQL 脚本SELECT 子品牌, 商品数字ID, COUNT(DISTINCT o.用户id) AS new_customer_num, SUM(o.商品实付金额) AS new_customer_商品实付金额 FROM 天猫官旗有效数据 o LEFT JOIN ( -- 找到22年10月30日前有购买行为的客户编号 SELECT 用户id FROM 天猫官旗有效数据 WHERE 支付日期 BETWEEN '2021-10-31' AND '2022-10-30' GROUP BY 用户id ) old_c ON o.用户id = old_c.用户id WHERE o.支付日期 >= '2022-10-31' AND o.支付日期 <= '2022-11-11' AND NOT EXISTS ( SELECT 1 FROM 天猫官旗有效数据 WHERE 用户id = o.用户id AND 支付日期 BETWEEN '2021-10-31' AND '2022-10-30') GROUP BY GROUPING SETS ((子品牌, 商品数字ID))

时间: 2024-01-24 07:17:55 浏览: 41
以下是优化后的MYSQL脚本: SELECT 子品牌, 商品数字ID, COUNT(DISTINCT CASE WHEN o.支付日期 >= '2022-10-31' AND o.支付日期 <= '2022-11-11' AND old_c.用户id IS NULL THEN o.用户id ELSE NULL END) AS new_customer_num, SUM(CASE WHEN o.支付日期 >= '2022-10-31' AND o.支付日期 <= '2022-11-11' AND old_c.用户id IS NULL THEN o.商品实付金额 ELSE 0 END) AS new_customer_商品实付金额 FROM 天猫官旗有效数据 o LEFT JOIN ( SELECT 用户id FROM 天猫官旗有效数据 WHERE 支付日期 BETWEEN '2021-10-31' AND '2022-10-30' GROUP BY 用户id ) old_c ON o.用户id = old_c.用户id WHERE o.支付日期 >= '2022-10-31' AND o.支付日期 <= '2022-11-11' GROUP BY 子品牌, 商品数字ID; 这里进行了以下优化: 1. CASE语句替代NOT EXISTS子查询,提高查询效率。 2. 将GROUPING SETS修改为普通的GROUP BY语句,简化查询语句。 3. 将条件判断移动到CASE语句中,减少不必要的计算。

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优化代码SELECT SUM(IF(order_date BETWEEN '2022-10-31' AND '2022-11-11' AND is_new_customer = 1, 1, 0)) AS new_customer_count, SUM(IF(order_date BETWEEN '2022-10-31' AND '2022-11-11' AND is_new_customer = 0, 1, 0)) AS old_customer_count, SUM(IF(order_date BETWEEN '2022-10-31' AND '2022-11-11' AND is_new_customer = 1, payment_amount, 0)) AS new_customer_payment_amount, SUM(IF(order_date BETWEEN '2022-10-31' AND '2022-11-11' AND is_new_customer = 0, payment_amount, 0)) AS old_customer_payment_amount, SUM(IF(order_date BETWEEN '2022-10-31' AND '2022-11-11' AND category = 'A', 1, 0)) AS category_A_customer_count, SUM(IF(order_date BETWEEN '2022-10-31' AND '2022-11-11' AND category = 'A', payment_amount, 0)) AS category_A_payment_amount, SUM(IF(order_date BETWEEN '2022-10-31' AND '2022-11-11' AND category = 'B', 1, 0)) AS category_B_customer_count, SUM(IF(order_date BETWEEN '2022-10-31' AND '2022-11-11' AND category = 'B', payment_amount, 0)) AS category_B_payment_amount, SUM(IF(order_date BETWEEN '2022-10-31' AND '2022-11-11' AND product_id = 'P1', 1, 0)) AS product_P1_customer_count, SUM(IF(order_date BETWEEN '2022-10-31' AND '2022-11-11' AND product_id = 'P1', payment_amount, 0)) AS product_P1_payment_amount FROM orders o LEFT JOIN (SELECT DISTINCT order_date FROM orders WHERE order_date BETWEEN '2022-10-31' AND '2022-11-11') d1 ON o.order_date = d1.order_date LEFT JOIN (SELECT DISTINCT order_date FROM orders WHERE order_date BETWEEN '2021-10-31' AND '2022-10-30' AND order_date NOT IN (SELECT order_date FROM orders WHERE order_date BETWEEN '2022-10-31' AND '2022-11-11')) d2 ON o.order_date = d2.order_date LEFT JOIN (SELECT DISTINCT order_date FROM orders WHERE order_date BETWEEN '2021-11-12' AND '2022-10-30' AND order_date IN (SELECT order_date FROM orders WHERE order_date BETWEEN '2022-10-31' AND '2022-11-11')) d3 ON o.order_date = d3.order_date WHERE d1.order_date IS NOT NULL OR d2.order_date IS NOT NULL OR d3.order_date IS NOT NULL;

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