Previous work has highlighted the involvement of many distributed cortical and subcortical regions to negative emotion perception and regulation (Vuilleumier and Pourtois, 2007;Kober et al., 2008; Lieberman et al., 2019; Lindquist et al., 2012;Citron, 2012 ). Commonly reported areas of the brain activated by negative events, relative to neutral stimulus, include visual cortices (fusiform cortex and lateral occipital cortex), amygdala, supramarginal gyrus, thalamus, cerebellum, parahippocampus, lateral orbitofrontal cortex, inferior frontal gyrus(Faten M. Aldhafeeri, rt al,2012;Schraa-Tam, et al, 2012;I. García-García, et al,2016). Among these regions, lesion studies in humans and animals have suggested the amygdala as a hub for threat detection and negative emotional experience (Adolphs et al., 2005; Davis et al., 2008).以上出自于哪一篇文献
时间: 2024-03-15 11:43:46 浏览: 146
我不知道这篇文献的具体名称,因为你没有提供这方面的信息。但是,这段话涉及了多个文献,包括Vuilleumier和Pourtois(2007)、Kober等人(2008)、Lieberman等人(2019)、Lindquist等人(2012)和Citron(2012),以及Faten M. Aldhafeeri等人(2012)、Schraa-Tam等人(2012)和I. García-García等人(2016)。
相关问题
README for navigating Sandia cell ARC Data • Name scheme = chemistry_state of charge_type of ARC • ARC plots in the manuscript are based on data recorded during the ‘exotherm’ mode of the ARC after it has completed ‘heat-wait-seek.’ This data is highlighted in the ‘Calculations’ tab for the EV-ARC files and the ‘Sheet 1’ tab for the ES-ARC files. • For the complete time course of the ARC experiment, including the ‘heat-wait-seek’ data, refer to the ‘Clean.DAT’ tab for the EV-ARC files and the ‘Data’ tab for the ES-ARC files. 含义
这段文本是关于导航三莱亚(Sandia)电池ARC数据的指南。其中介绍了命名方案,包括化学状态、电荷类型和ARC类型。在手稿中,ARC图是基于在完成“热门搜索”弧后的“排放室”模式中记录的数据。如果需要完整的时间课程数据,包括“热门搜索”数据,则需要参考EV-ARC文件的“Clean.dat”选项卡和ES-ARC文件的“数据”选项卡。这段文本还介绍了在EV-ARC文件的“Calculations”选项卡和ES-ARC文件的“Sheet 1”选项卡中强调的数据。
Design and implement a program in C, that receives as input from standard input: • a word w in the first line (no spaces, no more than 80 characters, word finishes with the new line, excluding this character), • an integer value n, between 0 and 127, in the second line, • an encoded text (all the text from the third line until the end of the input). The program then checks if when decoding the encoded text using n (each character is decremented, modulo 128, by n in its ASCII encoding), the word w is found. If so, the word ”YES” is printed out on standard output, highlighted in green. If not, then the word ”NO” is outputted on standard output, highlighted in red. You can assume that the encoded text is ASCII, and the input is formatted as indicated above.
Sure, I can help you with that. Here's a possible implementation of the program you described:
```c
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
#include <stdbool.h>
#define MAX_WORD_SIZE 80
#define ASCII_SIZE 128
void print_colored(char* text, char* color) {
printf("\033[%sm%s\033[0m", color, text);
}
bool decode_and_check(char* word, int n, char* encoded_text) {
int len = strlen(encoded_text);
char decoded_text[len + 1];
for (int i = 0; i < len; i++) {
decoded_text[i] = ((encoded_text[i] - n) % ASCII_SIZE + ASCII_SIZE) % ASCII_SIZE;
}
decoded_text[len] = '\0';
if (strstr(decoded_text, word) != NULL) {
return true;
} else {
return false;
}
}
int main() {
char word[MAX_WORD_SIZE + 1];
int n;
char encoded_text[ASCII_SIZE];
fgets(word, MAX_WORD_SIZE + 1, stdin);
scanf("%d", &n);
getchar(); // read the newline character after n
fgets(encoded_text, ASCII_SIZE, stdin);
encoded_text[strcspn(encoded_text, "\n")] = '\0'; // remove the newline character from encoded_text
if (decode_and_check(word, n, encoded_text)) {
print_colored("YES\n", "32"); // green color
} else {
print_colored("NO\n", "31"); // red color
}
return 0;
}
```
The program reads the input from standard input using `fgets()` and `scanf()`, and then applies the decoding algorithm to the `encoded_text` string using a loop and the `%` operator. The resulting `decoded_text` string is then checked for the presence of the `word` substring using `strstr()`. Finally, the program prints either "YES" or "NO" in the corresponding color using the `print_colored()` function and ANSI escape codes.
I hope this helps! Let me know if you have any questions.
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