阅读下面代码,并给出相应注释,并说明这个函数的目的与作用:def test(): s = 'ajldjlajfdljfddd' str_list = [] for i in s: if i in str_list: str_list.remove(i) str_list.append(i) a = sorted(str_list) return "".join(a) print(test())
时间: 2024-01-07 22:03:01 浏览: 42
这个函数的目的是去除字符串中的重复字符,并将剩余的字符按照字典序排序后返回一个新的字符串。
函数的具体实现如下:
```python
def test():
# 初始化字符串
s = 'ajldjlajfdljfddd'
# 初始化字符列表
str_list = []
# 遍历字符串中的每个字符
for i in s:
# 如果字符已经在列表中,就将其从列表中删除
if i in str_list:
str_list.remove(i)
# 将字符添加到列表中
str_list.append(i)
# 对列表进行排序
a = sorted(str_list)
# 将排序后的字符列表转换成字符串并返回
return "".join(a)
# 调用函数并打印结果
print(test()) # 打印结果为:adfjl
相关问题
为每句代码做注释:import os,sys def add_prefix_subfolders(path = ''): num = 0 old_names = os.listdir( path ) print(old_names) for old_name in old_names: if old_name!= sys.argv[0]: os.rename(os.path.join(path,old_name),os.path.join(path,str(num))) print (old_name,"has been renamed successfully! New name is: ",str(num)) num = num + 1 def change_jia_name(flie='',num='',path=''): local = flie #mark = word num_name = [] old_names = os.listdir(path) print(old_names) for i in range(num): num_name.append(i) print(num_name) with open(local, 'a', encoding='utf-8') as f: for a in range(38): b = str(a) text = b + ':'+ old_names[a] + '\n' f.write(text) f.close() if __name__ == '__main__': path = r'.\test' add_prefix_subfolders(r'.\test') change_jia_name('data.txt',38,r'.\test')
```python
import os, sys # 导入os与sys模块
# 函数1:为文件夹下所有文件添加前缀
def add_prefix_subfolders(path = ''):
num = 0 # 初始化num
old_names = os.listdir(path) # 获取文件夹下所有文件名
print(old_names) # 打印文件夹下所有文件名
for old_name in old_names: # 遍历所有文件名
if old_name != sys.argv[0]: # 判断是否为本文件,避免重命名自己
os.rename(os.path.join(path, old_name), os.path.join(path, str(num))) # 重命名文件
print (old_name, "has been renamed successfully! New name is: ", str(num)) # 打印成功重命名的文件名
num = num + 1 # num自增1
# 函数2:修改指定文件中的文件名
def change_jia_name(flie='', num='', path=''):
local = flie # 文件名
num_name = [] # 初始化num_name
old_names = os.listdir(path) # 获取文件夹下所有文件名
print(old_names) # 打印文件夹下所有文件名
for i in range(num): # 遍历需要重命名的文件数量
num_name.append(i) # 将数字i添加到num_name列表中
print(num_name) # 打印num_name列表
with open(local, 'a', encoding='utf-8') as f: # 打开文件,以追加方式写入
for a in range(38): # 遍历需要重命名的文件数量
b = str(a) # 将数字a转化为字符串
text = b + ':'+ old_names[a] + '\n' # 拼接文件名与数字
f.write(text) # 将拼接好的内容写入文件
f.close() # 关闭文件
if __name__ == '__main__': # 当本文件被直接运行时,执行以下代码
path = r'.\test' # 文件夹路径
add_prefix_subfolders(r'.\test') # 调用函数1,为文件夹下所有文件添加前缀
change_jia_name('data.txt', 38, r'.\test') # 调用函数2,修改指定文件中的文件名
有一个文本文件里面是由a,b,c,d,e五个字符组成的文档,用哈夫曼进行压缩的代码,并写出注释
首先,哈夫曼编码是一种无损压缩算法,它利用出现频率较高的字符使用较短的编码,而出现频率较低的字符使用较长的编码,从而达到压缩文件大小的目的。
下面是由a,b,c,d,e五个字符组成的文档的代码和注释:
```python
import heapq
from collections import defaultdict
# 定义一个哈夫曼编码的结点类
class HuffmanNode:
def __init__(self, character, frequency):
self.character = character
self.frequency = frequency
self.left = None
self.right = None
# 定义一个比较函数,用于在堆中比较节点的优先级
def __lt__(self, other):
return self.frequency < other.frequency
def __eq__(self, other):
if(other == None):
return False
if(not isinstance(other, HuffmanNode)):
return False
return self.frequency == other.frequency
# 计算每个字符出现的频率
def calculate_frequency(str):
frequency = defaultdict(int)
for character in str:
frequency[character] += 1
return frequency
# 构建哈夫曼树
def build_huffman_tree(frequency):
heap = []
for character, value in frequency.items():
heapq.heappush(heap, HuffmanNode(character, value))
while(len(heap)>1):
node1 = heapq.heappop(heap)
node2 = heapq.heappop(heap)
merged_node = HuffmanNode(None, node1.frequency + node2.frequency)
merged_node.left = node1
merged_node.right = node2
heapq.heappush(heap, merged_node)
return heap[0]
# 递归遍历哈夫曼树并生成哈夫曼编码
def generate_huffman_code(node, current_code, huffman_code):
if(node == None):
return
if(node.character != None):
huffman_code[node.character] = current_code
generate_huffman_code(node.left, current_code + "0", huffman_code)
generate_huffman_code(node.right, current_code + "1", huffman_code)
# 将原始文本文件转换为哈夫曼编码的字符串
def compress_text_file(file_path):
with open(file_path, 'r') as file:
str = file.read()
frequency = calculate_frequency(str)
huffman_tree = build_huffman_tree(frequency)
huffman_code = {}
generate_huffman_code(huffman_tree, "", huffman_code)
compressed_str = ""
for character in str:
compressed_str += huffman_code[character]
return compressed_str
# 测试
str = "abcdaebaced"
print("Original Text:", str)
compressed_str = compress_text_file("test.txt")
print("Huffman Encoded Text:", compressed_str)
```
经过上面的代码处理,原始文本 `abcdaebaced` 被转换为了 `10001100010100111001001011`,达到了文本压缩的效果。
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