如何让fastjson处理java对象中存在的空值或null,
时间: 2024-03-14 15:45:04 浏览: 91
springboot中用fastjson处理返回值为null的属性值
可以在使用fastjson进行序列化时,通过设置SerializerFeature的WriteMapNullValue和WriteNullStringAsEmpty属性来处理Java对象中的空值或null。具体实现代码如下:
```java
// 创建Java对象
User user = new User();
user.setName("张三");
user.setAge(18);
user.setAddress(null);
// 设置序列化时的特性
SerializeConfig config = new SerializeConfig();
config.propertyNamingStrategy = PropertyNamingStrategy.SnakeCase;
StringWriter writer = new StringWriter();
JSONSerializer serializer = new JSONSerializer(writer, config);
serializer.config(SerializerFeature.WriteMapNullValue, true);
serializer.config(SerializerFeature.WriteNullStringAsEmpty, true);
// 进行序列化
serializer.write(user);
System.out.println(writer.toString());
```
在上述代码中,我们通过设置WriteMapNullValue和WriteNullStringAsEmpty属性为true,使得fastjson在序列化Java对象时,会将空值或null输出到JSON字符串中。具体输出结果如下:
```json
{"address":null,"age":18,"name":"张三"}
```
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