C语言解答：有13个单词从小到大存入二维字符数组，用折半查找法找此单词“hello”，找到的话输出该单词和位置，找不到则输出“无此单词”。例如给定char words[][10]={"apple","balloon","disc","english","finish","girl","hello","link","pink","queen","rest","train","umbrella"};

ChitGPT:

好的，让我来解答这个问题。首先，我会用折半查找法来查找单词"hello"在二维字符数组中的位置。以下是代码示例：

#include <stdio.h>
#include <string.h>

char words[][10] = {"apple","balloon","disc","english","finish","girl","hello","link","pink","queen","rest","train","umbrella"};
int length = 13;

int binarySearch(char arr[][10], int l, int r, char* x) {
    if (r >= l) {
        int mid = l + (r - l) / 2;

        if (strcmp(arr[mid], x) == 0)
            return mid;

        if (strcmp(arr[mid], x) > 0)
            return binarySearch(arr, l, mid - 1, x);

        return binarySearch(arr, mid + 1, r, x);
    }

    return -1;
}

int main() {
    char word[] = "hello";
    int index = binarySearch(words, 0, length - 1, word);

    if (index != -1) {
        printf("单词 %s 位于第 %d 个位置\n", word, index);
    } else {
        printf("无此单词\n");
    }

    return 0;
}

输出结果为：

单词 hello 位于第 6 个位置

希望能够解决您的问题，如果您还有其他问题，请继续提问。