把行列数和左上右上右下坐标作为输入,根据这些信息求所有坐标的值,要求用C shap语言实现
时间: 2023-05-26 17:03:14 浏览: 43
由于任务描述不清晰,以下给出两种不同的实现思路:
1. 假设输入的是一个矩阵,且已知左上角和右下角坐标,可以使用双重循环遍历矩阵中的每个元素,找到符合要求的坐标,计算其值。
示例代码:
```
using System;
public class Program {
static void Main(string[] args) {
int rows = 4;
int cols = 5;
int[,] matrix = new int[rows, cols];
int leftRow = 1;
int leftCol = 1;
int rightRow = 3;
int rightCol = 4;
for (int i = 0; i < rows; i++) {
for (int j = 0; j < cols; j++) {
if (i >= leftRow && i <= rightRow && j >= leftCol && j <= rightCol) {
matrix[i, j] = i * j; // 具体计算方式可以根据需要修改
}
}
}
for (int i = 0; i < rows; i++) {
for (int j = 0; j < cols; j++) {
Console.Write($"{matrix[i, j]} ");
}
Console.WriteLine();
}
}
}
```
2. 假设输入的是行列数和左上、右上、右下三个坐标,可以先将左上和右下坐标转换为左下和右上坐标,然后分别计算每一行和每一列的增量,根据左下角坐标和行列增量得到所有坐标的值,最后计算每个坐标对应的值。
示例代码:
```
using System;
public class Program {
static void Main(string[] args) {
int rows = 4;
int cols = 5;
int leftUpRow = 1;
int leftUpCol = 1;
int rightUpRow = 1;
int rightUpCol = 4;
int rightDownRow = 2;
int rightDownCol = 4;
int leftDownRow = leftUpRow + rightDownRow - rightUpRow;
int leftDownCol = leftUpCol + rightDownCol - rightUpCol;
int rowStep = (rightDownRow - leftDownRow) / (cols - leftDownCol + 1);
int colStep = (rightUpCol - leftUpCol) / (rows - leftDownRow + 1);
int[,] matrix = new int[rows, cols];
for (int i = 0; i < rows; i++) {
for (int j = 0; j < cols; j++) {
int curRow = leftDownRow + i * rowStep;
int curCol = leftDownCol + j * colStep;
matrix[i, j] = curRow * curCol; // 具体计算方式可以根据需要修改
}
}
for (int i = 0; i < rows; i++) {
for (int j = 0; j < cols; j++) {
Console.Write($"{matrix[i, j]} ");
}
Console.WriteLine();
}
}
}
```