VAR := hello world all: @echo $(VAR) @echo $(strip $(VAR)) what is the printing value of thiis command? hello world hello world Aren't the two printling value the same? what the hell do you mean?
时间: 2024-01-18 18:05:16 浏览: 26
I apologize for the confusion. You are correct that in this case, both `echo` commands will print the same value.
The `$(strip)` function removes leading and trailing spaces from a string, but since the `VAR` variable in this case does not have any leading or trailing spaces, the output of `$(strip $(VAR))` will be the same as the output of `$(VAR)`.
So, if you run `make all` with the following Makefile code:
```
VAR := hello world
all:
@echo $(VAR)
@echo $(strip $(VAR))
```
The output will be:
```
hello world
hello world
```
I apologize for any confusion my previous response may have caused.
相关问题
VAR := hello world all: @echo $(VAR) @echo $(strip $(VAR)) what is the printing value of thiis command?
The `echo` command with `$(VAR)` will print the value of the `VAR` variable with leading and trailing spaces, while the `echo` command with `$(strip $(VAR))` will print the value of `VAR` with leading and trailing spaces removed.
So, if you run `make all` with the following Makefile code:
```
VAR := hello world
all:
@echo $(VAR)
@echo $(strip $(VAR))
```
The output will be:
```
hello world
hello world
```
Note that there is a space after the first output because `VAR` contains leading spaces. The second output does not have leading or trailing spaces.
假设有一段英文,其中有单独的字母i误写为i,请编写程序进行纠正
以下是Python代码示例:
```python
text = "Thiis iis a test striing wiith a miistake iin iit."
corrected_text = text.replace("iis", "is").replace("ii", "i")
print(corrected_text)
```
输出:
```
This is a test string with a mistake in it.
```
解释:
首先,我们将所有的 "iis" 替换为 "is",这样可以修正 "i" 和 "s" 连在一起的情况。
然后,我们将所有的 "ii" 替换为 "i",这样可以修正单独的 "i" 被误写成 "ii" 的情况。
最终,我们得到了纠正后的文本。