编写程序,实现一个自定义函数,计算两个序列中任意两点距离的最小值和最大值,以及距离最近和最远的两对点在点列中的序号。用自己的学号和学号反序的各位分别作为点的横坐标和纵坐标构造点列
时间: 2024-04-10 20:26:52 浏览: 134
好的,你可以使用以下代码来实现该自定义函数:
```python
import math
def calculate_distances(seq1, seq2):
points = [(int(str(seq1[i]) + str(seq1[::-1][i])), int(str(seq2[i]) + str(seq2[::-1][i]))) for i in range(len(seq1))]
min_dist = math.inf
max_dist = 0
min_dist_points = ()
max_dist_points = ()
for i in range(len(points) - 1):
for j in range(i + 1, len(points)):
dist = math.sqrt((points[i][0] - points[j][0])**2 + (points[i][1] - points[j][1])**2)
if dist < min_dist:
min_dist = dist
min_dist_points = (i, j)
if dist > max_dist:
max_dist = dist
max_dist_points = (i, j)
return min_dist, max_dist, min_dist_points, max_dist_points
```
这个函数接受两个序列 `seq1` 和 `seq2`,其中 `seq1` 是你的学号,`seq2` 是你学号反序的各位。它将构造一个点列,每个点的横坐标是 `seq1[i]` 和 `seq1[::-1][i]` 的组合,纵坐标是 `seq2[i]` 和 `seq2[::-1][i]` 的组合。然后,它会计算任意两点之间的距离,找到最小值和最大值,并返回距离最近和最远的两对点在点列中的序号。
你可以使用以下代码来测试该函数:
```python
seq1 = [1, 2, 3] # 你的学号
seq2 = [3, 2, 1] # 你学号反序的各位
min_dist, max_dist, min_dist_points, max_dist_points = calculate_distances(seq1, seq2)
print("最小距离:", min_dist)
print("最大距离:", max_dist)
print("距离最近的两对点序号:", min_dist_points)
print("距离最远的两对点序号:", max_dist_points)
```
请将 `seq1` 和 `seq2` 替换为你的学号和学号反序的各位,然后运行代码即可得到最小距离、最大距离以及距离最近和最远的两对点在点列中的序号。
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