编写一个Java应用程序求1!+2!+…+10!
时间: 2023-10-06 09:07:08 浏览: 66
下面是一个Java应用程序,用于计算1!+2!+...+10!的值:
```java
public class FactorialSum {
public static void main(String[] args) {
int n = 10; // 求和项数
int sum = 0; // 总和
for (int i = 1; i <= n; i++) {
sum += factorial(i); // 累加每一项的阶乘
}
System.out.println("1!+2!+...+10! = " + sum);
}
// 计算阶乘
public static int factorial(int n) {
int result = 1;
for (int i = 1; i <= n; i++) {
result *= i;
}
return result;
}
}
```
输出结果为:
```
1!+2!+...+10! = 4037913
```
相关问题
编写应用程序求1!+2!+3!+…+10!。
以下是两种Java语言编写应用程序求1!+2!+3!+…+10!的例子:
1.for循环和嵌套的for循环计算阶乘并求和
```java
public class FactorialSum {
public static void main(String[] args) {
int sum = 0;
for (int i = 1; i <= 10; i++) {
int factorial = 1;
for (int j = 1; j <= i; j++) {
factorial *= j;
}
sum += factorial;
}
System.out.println("1!+2!+3!+...+10!=" + sum);
}
}
```
2.使用递归函数调用阶乘方法求和
```java
public class FactorialSum {
public static void main(String[] args) {
int sum = 0;
for (int i = 1; i <= 10; i++) {
sum += factorial(i);
}
System.out.println("1!+2!+3!+...+10!=" + sum);
}
public static int factorial(int n) {
if (n == 1) {
return 1;
} else {
return n * factorial(n - 1);
}
}
}
```
java编写应用程序求1!+2!+...+10!。
您可以使用循环来计算1!到10!的结果。下面是使用Java编写的示例代码:
```java
public class Factorial {
public static void main(String[] args) {
// 计算1!到10!
for (int i = 1; i <= 10; i++) {
long factorial = getFactorial(i);
System.out.println(i + "! = " + factorial);
}
}
// 计算阶乘
public static long getFactorial(int n) {
long factorial = 1;
for (int i = 1; i <= n; i++) {
factorial *= i;
}
return factorial;
}
}
```
输出结果为:
```
1! = 1
2! = 2
3! = 6
4! = 24
5! = 120
6! = 720
7! = 5040
8! = 40320
9! = 362880
10! = 3628800
```