public static List<Double> solveByGauss(int n, List<List<Double>> matrix)是什么意思
时间: 2024-05-22 12:15:14 浏览: 174
这是一个Java函数,函数名为solveByGauss,接受两个参数,一个整数n和一个二维列表matrix。函数返回一个Double类型的列表。该函数的作用是使用高斯消元法(Gauss elimination)求解线性方程组。
参数n表示线性方程组的未知数个数,matrix表示系数矩阵。具体来说,matrix是一个n行n+1列的矩阵,前n列为系数矩阵,第n+1列为常数项。
函数返回的列表中包含了解的各个未知数的值。如果方程组无解,则返回空列表。
相关问题
在这个函数public static List<Double> solveByGauss(int n, List<List<Double>> matrix)中写一段代码,将List<List<Double>> matrix转换为二维数组
public static List<Double> solveByGauss(int n, List<List<Double>> matrix) {
double[][] arr = new double[n][n+1];
for (int i = 0; i < n; i++) {
for (int j = 0; j < n+1; j++) {
arr[i][j] = matrix.get(i).get(j);
}
}
// Gauss elimination algorithm implementation
// ...
List<Double> result = new ArrayList<>();
// ...
return result;
}
public static List<Double> solveByGauss(int n, List<List<Double>> matrix) { }完成高斯定理求线性代数方程solveByGause算法
public static List<Double> solveByGauss(int n, List<List<Double>> matrix) {
List<Double> solution = new ArrayList<Double>();
// Applying Gaussian Elimination
for (int i = 0; i < n; i++) {
// Finding the row with maximum element in the i-th column
int maxRow = i;
for (int j = i + 1; j < n; j++) {
if (Math.abs(matrix.get(j).get(i)) > Math.abs(matrix.get(maxRow).get(i))) {
maxRow = j;
}
}
// Swapping the rows if necessary
List<Double> temp = matrix.get(i);
matrix.set(i, matrix.get(maxRow));
matrix.set(maxRow, temp);
// Performing row operations to make all elements below the i-th element in the i-th column zero
for (int j = i + 1; j < n; j++) {
double factor = matrix.get(j).get(i) / matrix.get(i).get(i);
for (int k = i + 1; k <= n; k++) {
matrix.get(j).set(k, matrix.get(j).get(k) - factor * matrix.get(i).get(k));
}
matrix.get(j).set(i, 0.0);
}
}
// Back substitution to get the values of the variables
for (int i = n - 1; i >= 0; i--) {
double sum = 0.0;
for (int j = i + 1; j < n; j++) {
sum += matrix.get(i).get(j) * solution.get(j);
}
double value = (matrix.get(i).get(n) - sum) / matrix.get(i).get(i);
solution.add(0, value);
}
return solution;
}
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