assume cs:code, ds:data data segment msg db 'The string is a palindrome','$' msg1 db 'The string is a palindrome','$' msg2 db 'The string is not a palindrome','$' strings db 'abccba', '1234321', 'sdsfds$','$' num_strings equ 3 str_len equ 7 data ends stack segment dw 100h dup(0) stack ends code segment start: mov ax, data mov ds, ax mov si, 0 ; 用si存储字符串的索引 mov cx, 0 mov cl, str_len dec cx mov di, cx ; 用di存储字符串的另一个索引(从后往前) shr cx, 1 mov bx, 0 cmp cx, bx jle palindrome ; 如果字符串长度为0或1,则直接判断是否为回文字符串 outer_loop: mov ah, 0 mov al, num_strings mul si ; 计算当前字符串在二维数组中的偏移量 add al, strings mov bx, ax ; 将偏移量存储在bx中 mov si, 0 ; 重置si和di mov di, str_len - 1 inner_loop: mov al, [bx+si] ; 从二维数组中读取字符 mov ah, [bx+di] cmp al, ah jne not_palindrome inc si dec di cmp si, di jle inner_loop palindrome: lea dx, msg1 mov ah, 09h int 21h inc si ; 检查下一个字符串 cmp si, num_strings jl outer_loop ; 如果还有字符串未判断,则继续循环 jmp exit_program not_palindrome: lea dx, msg2 mov ah, 09h int 21h inc si ; 检查下一个字符串 cmp si, num_strings jl outer_loop ; 如果还有字符串未判断,则继续循环 jmp exit_program exit_program: mov ah, 4ch int 21h code ends end start本题字符窜为空
时间: 2024-01-11 18:03:56 浏览: 50
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如果字符串为空,则会发生错误,因为程序会尝试读取空指针地址的内容。此时需要对程序进行修改,添加对空字符串的判断,避免程序崩溃。可以在循环开始前添加对字符串长度的判断,如果长度为0,则直接跳过该字符串的判断。修改后的代码如下:
```
assume cs:code, ds:data
data segment
msg db 'The string is a palindrome','$'
msg1 db 'The string is a palindrome','$'
msg2 db 'The string is not a palindrome','$'
strings db 'abccba', '1234321', 'sdsfds$','$'
num_strings equ 3
str_len equ 7
data ends
stack segment
dw 100h dup(0)
stack ends
code segment
start:
mov ax, data
mov ds, ax
mov si, 0 ; 用si存储字符串的索引
mov cx, 0
mov cl, str_len
dec cx
mov di, cx ; 用di存储字符串的另一个索引(从后往前)
shr cx, 1
mov bx, 0
cmp cx, bx
jle palindrome ; 如果字符串长度为0或1,则直接判断是否为回文字符串
outer_loop:
mov ah, 0
mov al, num_strings
mul si ; 计算当前字符串在二维数组中的偏移量
add al, strings
mov bx, ax ; 将偏移量存储在bx中
mov si, 0 ; 重置si和di
mov di, str_len - 1
; 判断字符串是否为空
mov al, [bx+si]
cmp al, '$'
je next_string
inner_loop:
mov al, [bx+si] ; 从二维数组中读取字符
mov ah, [bx+di]
cmp al, ah
jne not_palindrome
inc si
dec di
cmp si, di
jle inner_loop
palindrome:
lea dx, msg1
mov ah, 09h
int 21h
inc si ; 检查下一个字符串
cmp si, num_strings
jl outer_loop ; 如果还有字符串未判断,则继续循环
jmp exit_program
not_palindrome:
lea dx, msg2
mov ah, 09h
int 21h
inc si ; 检查下一个字符串
cmp si, num_strings
jl outer_loop ; 如果还有字符串未判断,则继续循环
jmp exit_program
next_string:
inc si ; 检查下一个字符串
cmp si, num_strings
jl outer_loop ; 如果还有字符串未判断,则继续循环
jmp exit_program
exit_program:
mov ah, 4ch
int 21h
code ends
end start
```
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