如何屏蔽#2825-D conversion from a string literal to char * is deprecated

这是因为 C++11 中不推荐将字符串字面量直接赋值给 char* 类型的变量，而推荐使用 const char* 类型。如果你确定你的代码不会造成潜在的安全问题，可以使用编译器指定的预处理器宏来屏蔽此警告。

在 gcc 编译器中，可以使用如下语句来屏蔽此警告：

#pragma GCC diagnostic ignored "-Wwrite-strings"

在 Visual Studio 编译器中，可以使用如下语句来屏蔽此警告：

#pragma warning(disable:4996)

但是需要注意的是，屏蔽警告不是解决问题的最佳方法。最好的做法是修改代码，使用 const char* 类型来代替 char* 类型。

相关问题

ISO C++11 does not allow conversion from string literal to 'char *'

This error message is related to the C programming language and occurs when you try to assign a string literal (a sequence of characters enclosed in double quotes) to a variable of type `char *` (a pointer to a character).

In C, string literals are stored in read-only memory and attempting to modify them can result in undefined behavior. Therefore, the language specification prohibits assigning a string literal to a `char *` variable, as this could lead to unintended modifications of the original string.

To fix this error, you can declare the variable as a `const char *` instead, which tells the compiler that the pointer is pointing to read-only memory and should not be modified. Alternatively, you can allocate memory dynamically using functions like `malloc()` or `calloc()` and copy the contents of the string literal to the newly allocated memory.

workspace/2.c/main.cpp:6:16: warning: ISO C++11 does not allow conversion from string literal to 'char *' [-Wwritable-strings] char *p ="1234567890"; ^ 1 warning generated.改正

可以将指针p的类型改为const char*，表示指向常量的指针，可以避免这个警告，改正后的代码如下：

#include <stdio.h>   
int main(void)      
{      
    char a = 1;      
    char c[] = "1234567890";      
    const char *p = "1234567890";      
    a = c[1];      
    a = p[1];      
    return 0;      
}

这样就不会出现警告了。