帮我写一个能在电脑上运行的数独小游戏

好的，我可以为您提供一个Python的数独小游戏，您可以在电脑上运行。

代码如下：

import pygame
import sudoku_generator
import time

# 初始化pygame
pygame.init()

# 定义颜色
BLACK = (0, 0, 0)
WHITE = (255, 255, 255)
GRAY = (128, 128, 128)
LIGHT_BLUE = (96, 216, 232)
LIGHT_YELLOW = (255, 244, 79)

# 设置屏幕大小和标题
size = (540, 600)
screen = pygame.display.set_mode(size)
pygame.display.set_caption("数独小游戏")

# 设定字体
font = pygame.font.SysFont('Arial', 30)

# 定义数独生成器
sudoku = sudoku_generator.SudokuGenerator()

# 生成数独谜题和答案
sudoku.generate()
puzzle = sudoku.puzzle
solution = sudoku.solution

# 定义方格的边长
square_size = 60

# 定义数独面板的位置和大小
board_x = (size[0] - square_size * 9) / 2
board_y = (size[1] - square_size * 9) / 2
board_width = square_size * 9
board_height = square_size * 9

# 定义选中的方格的位置和大小
selected_x = None
selected_y = None
selected_width = square_size
selected_height = square_size

# 定义游戏是否结束
game_over = False

# 定义数独面板的二维数组
board = [[0 for x in range(9)] for y in range(9)]

# 将谜题复制到数独面板中
for i in range(9):
    for j in range(9):
        board[i][j] = puzzle[i][j]

# 定义数独面板的函数
def draw_board():
    for i in range(9):
        for j in range(9):
            # 绘制方格
            pygame.draw.rect(screen, BLACK, [board_x + square_size * j, board_y + square_size * i, square_size, square_size], 2)
            # 绘制数字
            if board[i][j] != 0:
                text = font.render(str(board[i][j]), True, BLACK)
                text_rect = text.get_rect(center=(board_x + square_size * j + square_size / 2, board_y + square_size * i + square_size / 2))
                screen.blit(text, text_rect)

# 定义选中方格的函数
def draw_selected(x, y):
    pygame.draw.rect(screen, LIGHT_YELLOW, [board_x + square_size * x, board_y + square_size * y, selected_width, selected_height], 3)

# 定义检查数独是否已完成的函数
def check_board():
    for i in range(9):
        for j in range(9):
            if board[i][j] == 0:
                return False
    return True

# 游戏循环
clock = pygame.time.Clock()
while not game_over:

    # 处理事件
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            game_over = True
        elif event.type == pygame.MOUSEBUTTONDOWN:
            # 获取鼠标点击的位置
            pos = pygame.mouse.get_pos()
            # 判断是否点击了数独面板内的方格
            if board_x <= pos[0] <= board_x + board_width and board_y <= pos[1] <= board_y + board_height:
                selected_x = int((pos[0] - board_x) / square_size)
                selected_y = int((pos[1] - board_y) / square_size)
                # 如果点击的方格是谜题中的空格，选中该方格
                if puzzle[selected_y][selected_x] == 0:
                    draw_selected(selected_x, selected_y)
            else:
                selected_x = None
                selected_y = None

        elif event.type == pygame.KEYDOWN and selected_x is not None and selected_y is not None:
            # 如果按下数字键，将数字填入选中的方格
            if event.unicode.isdigit() and puzzle[selected_y][selected_x] == 0:
                board[selected_y][selected_x] = int(event.unicode)
                selected_x = None
                selected_y = None
            # 如果按下删除键，将选中的方格清空
            elif event.key == pygame.K_BACKSPACE or event.key == pygame.K_DELETE:
                board[selected_y][selected_x] = 0
                selected_x = None
                selected_y = None

    # 绘制屏幕
    screen.fill(WHITE)
    draw_board()
    if selected_x is not None and selected_y is not None:
        draw_selected(selected_x, selected_y)

    # 检查数独是否已完成
    if check_board():
        # 如果已完成，绘制背景色并显示"恭喜你，完成了！"的提示
        pygame.draw.rect(screen, LIGHT_BLUE, [board_x, board_y, board_width, board_height])
        text = font.render("恭喜你，完成了！", True, BLACK)
        text_rect = text.get_rect(center=(size[0] / 2, board_y - 50))
        screen.blit(text, text_rect)

    # 更新屏幕
    pygame.display.flip()

    # 控制帧率
    clock.tick(60)

# 退出游戏
pygame.quit()

这个数独小游戏使用了Pygame库，可以在终端中运行。您可以将代码保存为.py文件，然后在终端中运行。

运行后，您可以使用鼠标点击数独面板中的方格，然后按数字键将数字填入方格中。如果需要清空已填入的数字，可以按下删除键或退格键。当您完成数独后，屏幕会显示"恭喜你，完成了！"的提示。

希望这个数独小游戏能够带给您一些乐趣！