输出字典fruits中键值最大的键值对。完善代码。fruits = {"apple":10,"mango":12,"durian":20,"banana":5} m = 'apple' for key in fruits.keys(): #此段代码请完善 print('{}:{}'.format(m,fruits[m]))
时间: 2023-06-18 13:07:12 浏览: 371
fruits = {"apple":10,"mango":12,"durian":20,"banana":5}
m = 'apple'
for key in fruits.keys():
if fruits[key] > fruits[m]:
m = key
print('{}:{}'.format(m,fruits[m]))
相关问题
输出字典fruits中键值最大的键值对。 fruits ={"apple":10,"mango":12,"durian":20,"banana":5}
可以使用以下代码来输出字典fruits中键值最大的键值对:
```python
fruits = {"apple":10, "mango":12, "durian":20, "banana":5}
max_key = max(fruits, key=fruits.get)
max_value = fruits[max_key]
print(max_key, max_value)
```
输出结果为:
```
durian 20
```
输出字典fruits中键值最大的键值对。 fruits={"apple":10,"mango":12,"durian":20,"banana":5}
可以使用Python内置的max函数来实现,代码如下:
```python
fruits={"apple":10,"mango":12,"durian":20,"banana":5}
max_key = max(fruits, key=fruits.get)
max_value = fruits[max_key]
print(max_key, max_value)
```
输出结果为:
```
durian 20
```
其中,`max(fruits, key=fruits.get)`会返回字典fruits中值最大的键名,然后我们再通过`fruits[max_key]`获取对应的值即可。