用python 写一个五子棋 游戏

好的，我可以为您提供一个基于 Python 的简单五子棋游戏的代码示例，代码如下：

# 导入必要的库
import numpy as np
import pygame

# 定义常量
BOARD_SIZE = 15
CELL_SIZE = 50
LINE_WIDTH = 2
WINDOW_SIZE = (BOARD_SIZE * CELL_SIZE, BOARD_SIZE * CELL_SIZE)
BLACK = (0, 0, 0)
WHITE = (255, 255, 255)
GRAY = (128, 128, 128)

# 初始化游戏
pygame.init()
screen = pygame.display.set_mode(WINDOW_SIZE)
pygame.display.set_caption("五子棋")
font = pygame.font.SysFont(None, 30)

# 创建棋盘
board = np.zeros((BOARD_SIZE, BOARD_SIZE), dtype=int)

# 定义函数：绘制棋盘
def draw_board():
    # 绘制背景
    screen.fill(WHITE)
    # 绘制线条
    for i in range(BOARD_SIZE):
        pygame.draw.line(screen, BLACK, (0, i * CELL_SIZE), (BOARD_SIZE * CELL_SIZE, i * CELL_SIZE), LINE_WIDTH)
        pygame.draw.line(screen, BLACK, (i * CELL_SIZE, 0), (i * CELL_SIZE, BOARD_SIZE * CELL_SIZE), LINE_WIDTH)
    # 绘制星位
    for i in [3, 11]:
        for j in [3, 11]:
            pygame.draw.circle(screen, BLACK, (i * CELL_SIZE, j * CELL_SIZE), 5, 0)

# 定义函数：绘制棋子
def draw_piece(row, col, player):
    pygame.draw.circle(screen, BLACK if player == 1 else WHITE, (col * CELL_SIZE, row * CELL_SIZE), CELL_SIZE // 2 - 5, 0)

# 定义函数：判断胜负
def check_win(row, col, player):
    # 判断横向是否连成五子
    count = 1
    for c in range(col - 1, -1, -1):
        if board[row][c] == player:
            count += 1
        else:
            break
    for c in range(col + 1, BOARD_SIZE):
        if board[row][c] == player:
            count += 1
        else:
            break
    if count >= 5:
        return True
    # 判断纵向是否连成五子
    count = 1
    for r in range(row - 1, -1, -1):
        if board[r][col] == player:
            count += 1
        else:
            break
    for r in range(row + 1, BOARD_SIZE):
        if board[r][col] == player:
            count += 1
        else:
            break
    if count >= 5:
        return True
    # 判断左上到右下是否连成五子
    count = 1
    r, c = row - 1, col - 1
    while r >= 0 and c >= 0:
        if board[r][c] == player:
            count += 1
        else:
            break
        r -= 1
        c -= 1
    r, c = row + 1, col + 1
    while r < BOARD_SIZE and c < BOARD_SIZE:
        if board[r][c] == player:
            count += 1
        else:
            break
        r += 1
        c += 1
    if count >= 5:
        return True
    # 判断左下到右上是否连成五子
    count = 1
    r, c = row + 1, col - 1
    while r < BOARD_SIZE and c >= 0:
        if board[r][c] == player:
            count += 1
        else:
            break
        r += 1
        c -= 1
    r, c = row - 1, col + 1
    while r >= 0 and c < BOARD_SIZE:
        if board[r][c] == player:
            count += 1
        else:
            break
        r -= 1
        c += 1
    if count >= 5:
        return True
    # 未连成五子，返回False
    return False

# 定义变量：当前落子方
current_player = 1

# 游戏循环
running = True
while running:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            running = False
        elif event.type == pygame.MOUSEBUTTONDOWN:
            # 获取鼠标点击位置
            x, y = event.pos
            row, col = y // CELL_SIZE, x // CELL_SIZE
            # 判断该位置是否可落子
            if board[row][col] == 0:
                # 更新棋盘
                board[row][col] = current_player
                # 绘制棋子
                draw_piece(row, col, current_player)
                # 判断胜负
                if check_win(row, col, current_player):
                    message = "黑方胜利" if current_player == 1 else "白方胜利"
                    text = font.render(message, True, BLACK)
                    screen.blit(text, (10, 10))
                    pygame.display.update()
                    running = False
                # 切换落子方
                current_player = 2 if current_player == 1 else 1
    # 绘制棋盘
    draw_board()
    # 更新屏幕
    pygame.display.update()

# 退出游戏
pygame.quit()

这个示例代码实现的是一个简单的双人五子棋游戏，您可以在此基础上进行修改和完善，例如实现人机对战、添加音效等等。