使用用pyhton的for写一个5门课程的求和
时间: 2024-05-03 20:23:36 浏览: 96
当然,我很愿意为你解答这道题目。以下是使用Python的for循环来求5门课程的和的代码:
```python
grades = [85, 92, 78, 90, 86]
total_grade = 0
for grade in grades:
total_grade += grade
print("五门课程的总成绩为:" + str(total_grade))
```
希望这个答案能够帮到你。如果你还有其它关于编程的问题,欢迎随时向我提问哦。
相关问题
使用pyhton语言写一个双向链表
首先,我们需要定义一个节点类,包括数据域和两个指针域,一个向前指针和一个向后指针:
```python
class Node:
def __init__(self, data):
self.data = data
self.prev = None
self.next = None
```
然后我们再定义一个双向链表类,包括头指针、尾指针和节点数量,以及各种操作的方法:
```python
class DoublyLinkedList:
def __init__(self):
self.head = None
self.tail = None
self.count = 0
def append(self, data):
"""在尾部添加节点"""
new_node = Node(data)
if self.head is None:
self.head = new_node
self.tail = new_node
else:
new_node.prev = self.tail
self.tail.next = new_node
self.tail = new_node
self.count += 1
def delete(self, node):
"""删除节点"""
if self.head is None or node is None:
return
if self.head == node:
self.head = node.next
if self.tail == node:
self.tail = node.prev
if node.prev is not None:
node.prev.next = node.next
if node.next is not None:
node.next.prev = node.prev
self.count -= 1
def find(self, data):
"""查找节点"""
current = self.head
while current is not None:
if current.data == data:
return current
current = current.next
return None
def print_list(self):
"""打印链表"""
current = self.head
while current is not None:
print(current.data, end=' ')
current = current.next
print()
```
这样就可以使用双向链表了,例如:
```python
dl_list = DoublyLinkedList()
dl_list.append(1)
dl_list.append(2)
dl_list.append(3)
dl_list.append(4)
dl_list.print_list() # 输出 1 2 3 4
node = dl_list.find(3)
dl_list.delete(
使用pyhton写一份扫雷源代码
当然可以,这里是一个简单的Python扫雷游戏的简单源码示例。这个版本是一个控制台版的基本游戏,它创建了一个迷宫式的矩阵,玩家需要找出地雷而不触动它们。
```python
import random
# 定义一个二维列表表示棋盘和地雷
class Minesweeper:
def __init__(self, size=10):
self.board = [['?' for _ in range(size)] for _ in range(size)]
self.mines = random.sample(range(size*size), size)
self.revealed_mines = set()
def reveal(self, x, y):
if (x, y) not in self.revealed_mines and (x, y) != ('?', ''):
num_neighbours_with_mine = self.count_neighbours(x, y)
self.board[x][y] = str(num_neighbours_with_mine)
if num_neighbours_with_mine == 0:
self.reveal_adjacent(x, y)
def count_neighbours(self, x, y):
count = 0
directions = [(dx, dy) for dx, dy in ((-1, -1), (-1, 0), (-1, 1),
(0, -1), (0, 1),
(1, -1), (1, 0), (1, 1)]
for dx, dy in directions:
nx, ny = x + dx, y + dy
if 0 <= nx < len(self.board) and 0 <= ny < len(self.board[0]) and (nx, ny) not in self.revealed_mines:
if (nx, ny) in self.mines:
count += 1
return count
def reveal_adjacent(self, x, y):
if x > 0 and (x-1, y) not in self.revealed_mines:
self.reveal(x-1, y)
if x < len(self.board)-1 and (x+1, y) not in self.revealed_mines:
self.reveal(x+1, y)
if y > 0 and (x, y-1) not in self.revealed_mines:
self.reveal(x, y-1)
if y < len(self.board[0])-1 and (x, y+1) not in self.revealed_mines:
self.reveal(x, y+1)
if __name__ == "__main__":
game = Minesweeper()
while True:
print(' '.join(row) for row in game.board)
try:
x, y = map(int, input("Enter coordinates (separated by space): ").split())
game.reveal(x, y)
except ValueError:
print("Invalid input, please enter two numbers.")
except IndexError:
print("Outside the grid, please try again.")
if all(coord in game.revealed_mines or coord == '?' for row in game.board for coord in row):
print("Congratulations! You found all the mines!")
break
elif any(coord == '*' for row in game.board for coord in row):
print("Game over! You touched a mine.")
break
```
你可以复制这段代码到一个`.py`文件中运行,并按照提示操作开始玩扫雷游戏。注意,这是一个基础版本,实际的游戏可能需要更复杂的用户界面和输入验证。
阅读全文