用c编写一个五子棋程序

下面是一个简单的五子棋程序示例，使用C语言编写：

#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>

#define BOARD_SIZE 15

char board[BOARD_SIZE][BOARD_SIZE];

// 清空棋盘
void clear_board() {
    for (int i = 0; i < BOARD_SIZE; i++) {
        for (int j = 0; j < BOARD_SIZE; j++) {
            board[i][j] = '+';
        }
    }
}

// 打印棋盘
void print_board() {
    printf("  ");
    for (int i = 0; i < BOARD_SIZE; i++) {
        printf("%d ", i + 1);
    }
    printf("\n");
    for (int i = 0; i < BOARD_SIZE; i++) {
        printf("%c ", i + 'A');
        for (int j = 0; j < BOARD_SIZE; j++) {
            printf("%c ", board[i][j]);
        }
        printf("\n");
    }
}

// 判断是否有五子连珠
bool check_win(int x, int y) {
    char player = board[x][y];
    int count = 1;

    // 横向检查
    for (int i = y - 1; i >= 0 && board[x][i] == player; i--) {
        count++;
    }
    for (int i = y + 1; i < BOARD_SIZE && board[x][i] == player; i++) {
        count++;
    }
    if (count >= 5) {
        return true;
    }

    // 纵向检查
    count = 1;
    for (int i = x - 1; i >= 0 && board[i][y] == player; i--) {
        count++;
    }
    for (int i = x + 1; i < BOARD_SIZE && board[i][y] == player; i++) {
        count++;
    }
    if (count >= 5) {
        return true;
    }

    // 左上-右下检查
    count = 1;
    for (int i = x - 1, j = y - 1; i >= 0 && j >= 0 && board[i][j] == player; i--, j--) {
        count++;
    }
    for (int i = x + 1, j = y + 1; i < BOARD_SIZE && j < BOARD_SIZE && board[i][j] == player; i++, j++) {
        count++;
    }
    if (count >= 5) {
        return true;
    }

    // 右上-左下检查
    count = 1;
    for (int i = x - 1, j = y + 1; i >= 0 && j < BOARD_SIZE && board[i][j] == player; i--, j++) {
        count++;
    }
    for (int i = x + 1, j = y - 1; i < BOARD_SIZE && j >= 0 && board[i][j] == player; i++, j--) {
        count++;
    }
    if (count >= 5) {
        return true;
    }

    return false;
}

int main() {
    clear_board();
    print_board();

    int x, y;
    char player = 'O';
    while (true) {
        printf("Player %c's turn, enter move (e.g. A1): ", player);
        scanf("%c%d", &x, &y);
        getchar();  // 消耗多余的换行符

        x -= 'A';  // 将字符转换为数字
        y--;

        if (x < 0 || x >= BOARD_SIZE || y < 0 || y >= BOARD_SIZE) {
            printf("Invalid move, please try again.\n");
            continue;
        }

        if (board[x][y] != '+') {
            printf("That cell is already occupied, please try again.\n");
            continue;
        }

        board[x][y] = player;
        print_board();

        if (check_win(x, y)) {
            printf("Player %c wins!\n", player);
            break;
        }

        // 切换到另一个玩家
        player = (player == 'O') ? 'X' : 'O';
    }

    return 0;
}

这个程序实现了一个简单的五子棋游戏，可以在终端中运行。玩家轮流输入坐标进行下棋，程序会判断是否有五子连珠，如果有则输出胜利信息并结束游戏。