帮我写一份蜘蛛纸牌的实现代码

好的，以下是一个简单的蜘蛛纸牌实现代码（使用Python语言）：

import random

# 初始化牌组
def init_deck():
    suits = ['♠', '♥', '♦', '♣']
    ranks = ['A', '2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K']
    deck = []
    for suit in suits:
        for rank in ranks:
            card = rank + suit
            deck.append(card)
    return deck

# 洗牌
def shuffle(deck):
    random.shuffle(deck)

# 发牌
def deal(deck, num):
    hand = deck[:num]
    del deck[:num]
    return hand

# 检查牌是否可移动
def is_valid_move(card1, card2):
    rank1, suit1 = card1[:-1], card1[-1]
    rank2, suit2 = card2[:-1], card2[-1]
    if suit1 == suit2:
        if abs(int(rank1) - int(rank2)) == 1:
            return True
    elif suit1 != suit2:
        if rank1 == 'K' and rank2 == 'A':
            return True
        elif rank1 == 'A' and rank2 == 'K':
            return True
    return False

# 检查是否胜利
def is_winner(piles):
    for pile in piles:
        if len(pile) != 13:
            return False
    return True

# 主程序
def play():
    deck = init_deck()
    shuffle(deck)
    piles = [[] for _ in range(10)]
    for i in range(4):
        piles[i].append(deal(deck, 1)[0])
    for i in range(4, 10):
        piles[i] = deal(deck, 6)
    while not is_winner(piles):
        print('----------------------------------------')
        print('牌堆情况：')
        for i in range(10):
            print('Pile {}: {}'.format(i+1, ' '.join(piles[i])))
        print('----------------------------------------')
        source_pile = int(input('请输入要移动的牌堆编号：'))
        dest_pile = int(input('请输入要移动到的牌堆编号：'))
        source_card = piles[source_pile-1][-1]
        dest_card = piles[dest_pile-1][-1] if piles[dest_pile-1] else None
        if not dest_card or is_valid_move(source_card, dest_card):
            piles[dest_pile-1].append(source_card)
            del piles[source_pile-1][-1]
        else:
            print('不合法的移动！')
    print('恭喜你，胜利了！')

if __name__ == '__main__':
    play()

注意：这只是一个简单的蜘蛛纸牌实现，可能还有很多细节需要完善。