c语言建立一个链表,每个结点包括姓名和成绩,c语言编程题，程序功能： 建立一个链表，每个结点包括：学号、姓名、性别、年龄，输入一个学号，如果链表中...

好的，这是一个比较复杂的问题，需要较长的代码实现。以下是一个简单的实现：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

// 定义链表节点结构体
typedef struct student {
    int id;
    char name[20];
    int score;
    struct student* next;
} Student;

// 定义链表头指针
Student* head = NULL;

// 插入节点函数
void insertNode(int id, char name[], int score) {
    Student* newNode = (Student*)malloc(sizeof(Student));
    newNode->id = id;
    strcpy(newNode->name, name);
    newNode->score = score;
    newNode->next = NULL;

    if (head == NULL) {
        head = newNode;
    } else {
        Student* current = head;
        while (current->next != NULL) {
            current = current->next;
        }
        current->next = newNode;
    }
}

// 查找节点函数
Student* findNode(int id) {
    Student* current = head;
    while (current != NULL) {
        if (current->id == id) {
            return current;
        }
        current = current->next;
    }
    return NULL;
}

// 输出链表函数
void printList() {
    Student* current = head;
    while (current != NULL) {
        printf("id: %d, name: %s, score: %d\n", current->id, current->name, current->score);
        current = current->next;
    }
}

int main() {
    // 插入节点
    insertNode(1, "Tom", 90);
    insertNode(2, "Jerry", 80);
    insertNode(3, "Lucy", 70);

    // 查找节点并输出结果
    int id;
    printf("Enter student id to search: ");
    scanf("%d", &id);
    Student* node = findNode(id);
    if (node != NULL) {
        printf("id: %d, name: %s, score: %d\n", node->id, node->name, node->score);
    } else {
        printf("Student not found.\n");
    }

    // 输出链表
    printList();

    return 0;
}

这个程序会创建一个链表，每个节点包括学号、姓名和成绩。它还会提示用户输入一个学号，然后查找链表中是否有对应的节点，并输出其姓名和成绩。最后，它会输出整个链表的内容。