使用优先级调度算法和时间轮片算法来模拟进程调度(C语言)
时间: 2023-06-27 22:06:53 浏览: 58
下面给出使用优先级调度算法和时间轮片算法来模拟进程调度的示例代码:
优先级调度算法:
```c
#include <stdio.h>
#define MAX_PROCESS_NUM 10
struct process {
int pid; // 进程ID
int priority; // 进程优先级
};
int main() {
struct process processes[MAX_PROCESS_NUM] = {
{1, 5},
{2, 7},
{3, 3},
{4, 1},
{5, 8},
{6, 2},
{7, 9},
{8, 6},
{9, 4},
{10, 10}
};
// 对进程按照优先级进行排序
for (int i = 0; i < MAX_PROCESS_NUM - 1; i++) {
for (int j = i + 1; j < MAX_PROCESS_NUM; j++) {
if (processes[i].priority < processes[j].priority) {
struct process temp = processes[i];
processes[i] = processes[j];
processes[j] = temp;
}
}
}
// 模拟进程执行
for (int i = 0; i < MAX_PROCESS_NUM; i++) {
printf("执行进程 %d,优先级为 %d\n", processes[i].pid, processes[i].priority);
}
return 0;
}
```
时间轮片算法:
```c
#include <stdio.h>
#define MAX_PROCESS_NUM 10
#define MAX_TIME_SLICE 3
struct process {
int pid; // 进程ID
int time_left; // 进程剩余执行时间
};
int main() {
struct process processes[MAX_PROCESS_NUM] = {
{1, 4},
{2, 7},
{3, 2},
{4, 5},
{5, 3},
{6, 6},
{7, 1},
{8, 8},
{9, 2},
{10, 4}
};
// 模拟进程执行
int current_process = 0;
while (1) {
printf("执行进程 %d,剩余时间片为 %d\n", processes[current_process].pid, MAX_TIME_SLICE);
processes[current_process].time_left -= MAX_TIME_SLICE;
if (processes[current_process].time_left <= 0) {
printf("进程 %d 执行完毕\n", processes[current_process].pid);
current_process++;
if (current_process == MAX_PROCESS_NUM) {
break;
}
}
}
return 0;
}
```
注意:以上代码仅为示例,实际情况中需要根据具体需求进行调整。