用play_game写一段猜拳游戏的pyhton代码，一轮游戏之后询问是否继续游戏，若选择是，则继续，选择否，则程序终止

好的，以下是猜拳游戏的Python代码：

import random

while True:
    # 提示用户输入猜拳手势
    print("请出拳：1-石头，2-剪刀，3-布")
    player = int(input())

    # 判断输入是否合法
    if player not in [1, 2, 3]:
        print("输入无效，请重新输入！")
        continue

    # 电脑随机出拳
    computer = random.randint(1, 3)

    # 宣布胜负
    if player == computer:
        print("平局！")
    elif (player == 1 and computer == 2) or (player == 2 and computer == 3) or (player == 3 and computer == 1):
        print("你赢了！")
    else:
        print("你输了！")

    # 询问是否继续游戏
    print("是否继续？（是/否）")
    choice = input()
    if choice == "否":
        break

请问还有其他问题吗？

相关问题

用play_game写一段猜拳游戏的pyhton代码

好的，以下是用 Python 编写的一个简单的猜拳游戏代码：

import random

def play_game():
    options = ['rock', 'paper', 'scissors']
    computer_choice = random.choice(options)
    user_choice = input("Please choose rock, paper or scissors: ")
    print("You chose:", user_choice)
    print("Computer chose:", computer_choice)
    if user_choice == computer_choice:
        print("It's a tie!")
    elif (user_choice == 'rock' and computer_choice == 'scissors') or (user_choice == 'paper' and computer_choice == 'rock') or (user_choice == 'scissors' and computer_choice == 'paper'):
        print("You win!")
    else:
        print("Computer wins!")

play_game()

调用 play_game() 函数即可开始游戏。每次游戏都随机生成电脑的出拳，用户通过输入 'rock'、'paper' 或 'scissors' 进行猜拳，程序会根据规则判断胜负并输出结果。

写一个贪吃蛇pyhton代码

### 回答1：

我可以给你一些简单的Python代码来实现贪吃蛇：import pygame
import sys
import random# 初始化游戏
pygame.init()# 设置窗口
game_width = 800
game_height = 600
game_window = pygame.display.set_mode((game_width, game_height))
pygame.display.set_caption("贪吃蛇")# 颜色
white = (255, 255, 255)
black = (0, 0, 0)
red = (255, 0, 0)
green = (0, 255, 0)# 定义蛇的起始位置
snake_x = 400
snake_y = 300# 定义蛇的大小
snake_size = 10# 蛇的移动方向
direction = "right"# 定义食物的位置
food_x = random.randint(0, game_width-snake_size)
food_y = random.randint(0, game_height-snake_size)# 设置循环条件
game_over = False# 开始游戏循环
while not game_over:
# 获取按键事件
for event in pygame.event.get():
# 如果按下了退出按钮，游戏结束
if event.type == pygame.QUIT:
game_over = True
# 如果按下了按键，改变蛇的移动方向
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
direction = "left"
if event.key == pygame.K_RIGHT:
direction = "right"
if event.key == pygame.K_UP:
direction = "up"
if event.key == pygame.K_DOWN:
direction = "down" # 更新蛇的位置
if direction == "right":
snake_x += 10
if direction == "left":
snake_x -= 10
if direction == "up":
snake_y -= 10
if direction == "down":
snake_y += 10 # 填充游戏窗口
game_window.fill(white)
# 画蛇
pygame.draw.rect(game_window, green, [snake_x, snake_y, snake_size, snake_size])
# 画食物
pygame.draw.rect(game_window, red, [food_x, food_y, snake_size, snake_size])
# 刷新游戏窗口
pygame.display.update()# 退出游戏
pygame.quit()
sys.exit()

### 回答2：
贪吃蛇是一款经典的游戏，下面是一个基于Python的贪吃蛇代码：

import pygame
import random

# 初始化游戏
pygame.init()

# 设置游戏窗口大小
window_width = 600
window_height = 400

# 创建游戏窗口
window = pygame.display.set_mode((window_width, window_height))
pygame.display.set_caption("贪吃蛇")

# 定义游戏相关参数
snake_size = 20
snake_speed = 10

# 定义颜色
white = (255, 255, 255)
black = (0, 0, 0)
red = (255, 0, 0)

# 定义贪吃蛇的初始位置
snake_x = window_width / 2
snake_y = window_height / 2

# 定义贪吃蛇的移动方向
snake_dx = 0
snake_dy = 0

# 定义食物的初始位置
food_x = round(random.randrange(0, window_width - snake_size) / 20) * 20
food_y = round(random.randrange(0, window_height - snake_size) / 20) * 20

# 定义得分
score = 0

# 控制游戏循环退出的变量
game_over = False

# 控制游戏帧率
clock = pygame.time.Clock()

# 定义贪吃蛇身体
snake_body = []
snake_body_length = 1

# 游戏循环
while not game_over:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            game_over = True
        elif event.type == pygame.KEYDOWN:
            if event.key == pygame.K_LEFT:
                snake_dx = -snake_size
                snake_dy = 0
            elif event.key == pygame.K_RIGHT:
                snake_dx = snake_size
                snake_dy = 0
            elif event.key == pygame.K_UP:
                snake_dx = 0
                snake_dy = -snake_size
            elif event.key == pygame.K_DOWN:
                snake_dx = 0
                snake_dy = snake_size

    # 更新贪吃蛇头部位置
    snake_x += snake_dx
    snake_y += snake_dy

    # 判断是否吃到食物
    if snake_x == food_x and snake_y == food_y:
        food_x = round(random.randrange(0, window_width - snake_size) / 20) * 20
        food_y = round(random.randrange(0, window_height - snake_size) / 20) * 20
        score += 1
        snake_body_length += 1

    # 更新贪吃蛇身体
    snake_head = []
    snake_head.append(snake_x)
    snake_head.append(snake_y)
    snake_body.append(snake_head)
    if len(snake_body) > snake_body_length:
        del snake_body[0]

    # 判断是否游戏结束
    if snake_x < 0 or snake_x >= window_width or snake_y < 0 or snake_y >= window_height:
        game_over = True
        print("游戏结束，得分：%d" % score)
    for item in snake_body[:-1]:
        if item == snake_head:
            game_over = True
            print("游戏结束，得分：%d" % score)

    # 填充窗口背景色
    window.fill(black)

    # 绘制贪吃蛇和食物
    for item in snake_body:
        pygame.draw.rect(window, white, [item[0], item[1], snake_size, snake_size])
    pygame.draw.rect(window, red, [food_x, food_y, snake_size, snake_size])

    # 更新窗口显示
    pygame.display.update()

    # 控制游戏帧率
    clock.tick(snake_speed)

# 退出游戏
pygame.quit()

这段代码实现了一个简单的贪吃蛇游戏，玩家通过键盘上下左右箭头控制蛇头移动，吃到食物后得分增加，当蛇头撞墙或者撞到自己身体时游戏结束，最终会有一个得分的输出。游戏使用Pygame库来实现窗口和图形的显示，通过不断更新贪吃蛇的位置来实现蛇的移动，并判断游戏是否结束。

### 回答3：
下面是一个简单的 Python 贪吃蛇代码：

import pygame
import random

# 初始化游戏
pygame.init()

# 游戏窗口大小
width = 800
height = 600

# 颜色
white = (255, 255, 255)
black = (0, 0, 0)
red = (255, 0, 0)

# 初始化游戏窗口
game_display = pygame.display.set_mode((width, height))
pygame.display.set_caption('贪吃蛇')

# 游戏速度（贪吃蛇移动的速度）
clock = pygame.time.Clock()
snake_block = 20
snake_speed = 20

font_style = pygame.font.SysFont(None, 50)
score_font = pygame.font.SysFont(None, 35)

def our_snake(snake_block, snake_list):
    for x in snake_list:
        pygame.draw.rect(game_display, black, [x[0], x[1], snake_block, snake_block])

def message(msg, color):
    mesg = font_style.render(msg, True, color)
    game_display.blit(mesg, [width / 6, height / 3])

# 游戏主循环
def game_loop():

    game_over = False
    game_close = False

    # 初始位置
    x1 = width/2
    y1 = height/2

    # 移动方向
    x1_change = 0       
    y1_change = 0

    # 初始长度
    snake_List = []
    Length_of_snake = 1

    # 随机生成食物位置
    foodx = round(random.randrange(0, width - snake_block) / 20.0) * 20.0
    foody = round(random.randrange(0, height - snake_block) / 20.0) * 20.0

    while not game_over:

        while game_close == True:
            game_display.fill(white)
            message("You lost! Press Q-Quit or C-Play Again", red)
            pygame.display.update()

            # 处理游戏结束事件
            for event in pygame.event.get():
                if event.type == pygame.KEYDOWN:
                    if event.key == pygame.K_q:
                        game_over = True
                        game_close = False
                    if event.key == pygame.K_c:
                        game_loop()

        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                game_over = True

            if event.type == pygame.KEYDOWN:
                if event.key == pygame.K_LEFT:
                    x1_change = -snake_block
                    y1_change = 0
                elif event.key == pygame.K_RIGHT:
                    x1_change = snake_block
                    y1_change = 0
                elif event.key == pygame.K_UP:
                    y1_change = -snake_block
                    x1_change = 0
                elif event.key == pygame.K_DOWN:
                    y1_change = snake_block
                    x1_change = 0

        if x1 >= width or x1 < 0 or y1 >= height or y1 < 0:
            game_close = True
        x1 += x1_change
        y1 += y1_change
        game_display.fill(white)
        pygame.draw.rect(game_display, red, [foodx, foody, snake_block, snake_block])
        snake_Head = []
        snake_Head.append(x1)
        snake_Head.append(y1)
        snake_List.append(snake_Head)
        if len(snake_List) > Length_of_snake:
            del snake_List[0]

        for x in snake_List[:-1]:
            if x == snake_Head:
                game_close = True

        our_snake(snake_block, snake_List)
        pygame.display.update()

        if x1 == foodx and y1 == foody:
            foodx = round(random.randrange(0, width - snake_block) / 20.0) * 20.0
            foody = round(random.randrange(0, height - snake_block) / 20.0) * 20.0
            Length_of_snake += 1

        clock.tick(snake_speed)

    pygame.quit()

# 运行游戏
game_loop()

这段代码使用了 Python 中的 Pygame 模块创建了一个贪吃蛇游戏。在游戏中，玩家通过控制蛇的移动方向，将食物吃掉，并尽量避免撞到自己的身体或者游戏窗口的边界。游戏使用矩形来表示蛇的身体和食物，通过监听按键事件，改变蛇头的坐标实现蛇的移动。当蛇头与食物的坐标重合时，代表蛇吃到了食物，蛇的长度增加，食物会在窗口内的随机位置重新生成。当蛇头撞到自己的身体或者游戏窗口的边界时，游戏结束。