用pgzero做消消乐，给出源码

好的，以下是一个简单的用pgzero实现的消消乐游戏的源码，你可以根据自己的需求进行修改和优化。

import pgzrun
import random

WIDTH = 640
HEIGHT = 480
TITLE = "消消乐"

# 定义常量
ROW_COUNT = 8
COLUMN_COUNT = 8
BLOCK_WIDTH = 60
BLOCK_HEIGHT = 60
BLOCK_TYPES = 5
MAX_LEVEL = 5
BLOCK_IMAGES = ["block1", "block2", "block3", "block4", "block5"]

# 定义变量
block_list = []
selected_blocks = []
level = 1
score = 0


class Block:
    def __init__(self, image, row, column):
        self.image = image
        self.row = row
        self.column = column
        self.x = column * BLOCK_WIDTH + BLOCK_WIDTH // 2
        self.y = row * BLOCK_HEIGHT + BLOCK_HEIGHT // 2

    def draw(self):
        screen.blit(self.image, (self.x - BLOCK_WIDTH // 2, self.y - BLOCK_HEIGHT // 2))

    def is_selected(self):
        return self in selected_blocks


def load_images():
    block_images = []
    for image_name in BLOCK_IMAGES:
        block_images.append(load_image(image_name + ".png"))
    return block_images


def create_block(row, column):
    block_image = random.choice(block_images)
    block = Block(block_image, row, column)
    block_list.append(block)


def create_blocks():
    for row in range(ROW_COUNT):
        for column in range(COLUMN_COUNT):
            create_block(row, column)


def draw_blocks():
    for block in block_list:
        block.draw()


def get_block_at_position(x, y):
    for block in block_list:
        if abs(block.x - x) < BLOCK_WIDTH / 2 and abs(block.y - y) < BLOCK_HEIGHT / 2:
            return block
    return None


def remove_blocks():
    global score
    for block in selected_blocks:
        block_list.remove(block)
    score += len(selected_blocks)


def get_adjacent_blocks(block):
    adjacent_blocks = []
    for other_block in block_list:
        if other_block == block:
            continue
        if other_block.image == block.image:
            if other_block.row == block.row and abs(other_block.column - block.column) == 1:
                adjacent_blocks.append(other_block)
            elif other_block.column == block.column and abs(other_block.row - block.row) == 1:
                adjacent_blocks.append(other_block)
    return adjacent_blocks


def clear_selected_blocks():
    for block in selected_blocks:
        block.image = None
    selected_blocks.clear()


def is_game_over():
    return len(block_list) == 0


def on_mouse_down(pos):
    block = get_block_at_position(pos[0], pos[1])
    if not block:
        return
    if block.is_selected():
        block.image = None
        selected_blocks.remove(block)
        return
    if len(selected_blocks) == 2:
        clear_selected_blocks()
    selected_blocks.append(block)
    if len(selected_blocks) == 2:
        adjacent_blocks = get_adjacent_blocks(selected_blocks[0])
        if selected_blocks[1] in adjacent_blocks:
            remove_blocks()
            clear_selected_blocks()


def update():
    global level, score
    if is_game_over():
        level += 1
        if level > MAX_LEVEL:
            return
        create_blocks()


def draw():
    screen.clear()
    draw_blocks()
    screen.draw.text("Level: " + str(level), (10, 10), color="white")
    screen.draw.text("Score: " + str(score), (10, 30), color="white")


# 加载图像
block_images = load_images()

# 创建方块
create_blocks()

# 启动游戏
pgzrun.go()

这个实现和连连看游戏类似，但是消去方块的方式不同，游戏逻辑也有所不同。你可以根据自己的需求进行修改和优化。