module top_module; wsh wsh_inst(); efg efg_inst(); divider divider_inst(); assign divider_inst.dividend = wsh_inst.subdivision; assign divider_inst.divisor = efg_inst.count; endmodule module wsh (clk,rst_n,A,B,subdivision); input wire A,B; input clk; input rst_n; output reg [15:0] subdivision; reg [1:0] pre_state; reg [1:0] cur_state; always @(posedge clk or negedge rst_n) begin if(!rst_n) subdivision <=1'b0; else begin if (pre_state == 2'b00 && cur_state == 2'b01) subdivision <= subdivision + 1'b1; else if(pre_state == 2'b01 && cur_state == 2'b11) subdivision <= subdivision + 1'b1; else if(pre_state == 2'b11 && cur_state == 2'b10) subdivision <= subdivision + 1'b1; else if(pre_state == 2'b10 && cur_state == 2'b00) subdivision <= subdivision + 1'b1; else if(pre_state == 2'b00 && cur_state == 2'b10) subdivision <= subdivision - 1'b1; else if(pre_state == 2'b10 && cur_state == 2'b11) subdivision <= subdivision - 1'b1; else if(pre_state == 2'b11 && cur_state == 2'b01) subdivision <= subdivision - 1'b1; else if(pre_state == 2'b01 && cur_state == 2'b00) subdivision <= subdivision - 1'b1; end end endmodule module efg (A,B,count,clk,rst_n); input wire A; input wire B; input clk; input rst_n; output reg [15:0] count; always @(posedge clk) begin if(!rst_n) count <= 0; else begin count <= count + 1; end end endmodule module divider(clk, subdivision, count, quotient); input clk; input [15:0] subdivision; input [15:0] count; output [15:0] quotient; reg [15:0] dividend; reg [15:0] divisor; reg [15:0] quotient; integer i; always @(posedge clk) begin dividend <= subdivision; divisor <= count; quotient <= 0; for (i = 0; i < 16; i = i + 1) begin dividend <= dividend - divisor; quotient <= {quotient[14:0], dividend[15]}; dividend <= dividend << 1; end end endmodule根据所给代码写一个testbench

以下是一个简单的testbench示例，使用Verilog语言：

module top_module_tb;

  // Inputs
  reg clk;
  reg rst_n;
  reg A;
  reg B;

  // Outputs
  wire [15:0] quotient;

  // Instantiate the design under test
  top_module dut (
    .clk(clk),
    .rst_n(rst_n),
    .A(A),
    .B(B),
    .quotient(quotient)
  );

  // Generate clock signal
  always #5 clk = ~clk;

  // Initialize inputs
  initial begin
    clk = 0;
    rst_n = 0;
    A = 0;
    B = 0;
  end

  // Reset the DUT
  initial begin
    #10 rst_n = 1;
  end

  // Test case 1
  initial begin
    #20 A = 4'b0000; // Dividend = 0
    B = 4'b0000; // Divisor = 0
    #20 A = 4'b1010; // Dividend = 10
    B = 4'b0010; // Divisor = 2
    #100; // Wait for division to complete
    $display("Quotient = %d", quotient);
    #20 $finish;
  end

endmodule

在测试用例中，我们将输入A和B设置为一些特定的值，并在一段时间后检查输出商的值。注意，在testbench中，我们使用了一个时钟信号来驱动DUT，并在每个上升沿之后对输入进行更改。我们还使用了一些延迟语句来模拟各种等待时间。