写个代码：Python背单词记单词小程序，可自定义词库，支持多种记忆模式，根据词义拼写、选择单词，根据词意选择单词，可乱序抽查，可对错题进行反复抽查

很抱歉，作为AI语言模型，我不支持真正的代码生成。一些 Python 编程语言的示例代码可示范如下：

# 背单词记单词小程序

import random

# 自定义词库
word_dict = {
    "apple": "苹果",
    "book": "书",
    "computer": "计算机",
    "dog": "狗",
    "eat": "吃",
    "friend": "朋友",
    "green": "绿色",
    "house": "房子",
    "internet": "互联网",
    "jump": "跳跃"
}

# 记忆模式（根据词义拼写、选择单词，根据词意选择单词）
modes = ["根据词义拼写", "选择单词", "根据词意选择单词"]

# 乱序抽查函数
def shuffle_dict(dict):
    keys = list(dict.keys())
    random.shuffle(keys)
    return {key: dict[key] for key in keys}

# 开始记忆
def start_learning():
    # 随机选取一个记忆模式
    mode = random.choice(modes)
    print("记忆模式：", mode)

    # 乱序选择一个单词
    shuffled_dict = shuffle_dict(word_dict)
    word = random.choice(list(shuffled_dict.keys()))

    # 根据不同的记忆模式，出题并检查答案
    if mode == "根据词义拼写":
        answer = input("单词的中文含义是： " + shuffled_dict[word] + "，请拼写出对应的英文单词：")
        if answer.lower() == word.lower():
            print("回答正确！")
        else:
            print("回答错误！正确答案是：", word)

    elif mode == "选择单词":
        options = [word] + random.sample(list(shuffled_dict.keys()), 3)
        random.shuffle(options)
        print("以下哪个单词的中文含义是：", shuffled_dict[word])
        for i in range(len(options)):
            print(i+1, options[i])
        answer = input()
        if answer.isdigit() and int(answer) in range(1, 5):
            choice = options[int(answer)-1]
            if choice == word:
                print("回答正确！")
            else:
                print("回答错误！正确答案是：", word)
        else:
            print("输入无效！")

    elif mode == "根据词意选择单词":
        cn_meaning = shuffled_dict[word]
        options = [word_dict[k] for k in shuffled_dict.keys() if shuffled_dict[k] != cn_meaning][:3] + [cn_meaning]
        random.shuffle(options)
        print("以下哪个单词是中文含义为“", cn_meaning, "”的英文单词？")
        for i in range(len(options)):
            print(i+1, options[i])
        answer = input()
        if answer.isdigit() and int(answer) in range(1, 5):
            choice = [k for k in shuffled_dict.keys() if shuffled_dict[k] == cn_meaning][0]
            if choice == list(shuffled_dict.keys())[int(answer)-1]:
                print("回答正确！")
            else:
                print("回答错误！正确答案是：", choice)
        else:
            print("输入无效！")

# 反复抽查错题
def review():
    while True:
        # 随机选择一个错题
        wrong_words = [k for k in word_dict.keys() if input("是否熟悉此单词？（y/n）" + k) == "n"]
        if len(wrong_words) == 0:
            print("所有错题已经复习完毕！")
            break
        wrong_word = random.choice(wrong_words)
        print(wrong_word, word_dict[wrong_word])
        start_learning()

# 主程序
while True:
    answer = input("请输入操作指令：\n1. 开始记忆\n2. 反复抽查错题\n3. 退出\n")
    if answer == "1":
        start_learning()
    elif answer == "2":
        review()
    elif answer == "3":
        break
    else:
        print("输入无效！")

这只是一个简单的背单词小程序示例，您可以根据自己的需要进行修改和扩展。