编写 Python 程序,验证推理的有效性: (1)(Q→R),Q R。 (2)(P→Q) (Q→R), (P→R)。使之能在pycharm运行
时间: 2024-03-05 07:48:22 浏览: 28
以下是Python代码,可以验证给定的两个推理是否有效:
```python
# 验证推理 (Q→R),Q R 的有效性
print('(Q→R),Q R')
print('Q\tR\tQ→R\t(Q→R),Q\tR')
for Q in [True, False]:
for R in [True, False]:
Q_implies_R = not Q or R
Q_implies_R_and_Q = Q_implies_R and Q
result = Q_implies_R_and_Q <= R
print('{}\t{}\t{}\t{}\t{}'.format(Q, R, Q_implies_R, Q_implies_R_and_Q, result))
# 验证推理 (P→Q) (Q→R), (P→R) 的有效性
print('\n(P→Q) (Q→R), (P→R)')
print('P\tQ\tR\tP→Q\tQ→R\t(P→Q) (Q→R)\tP→R')
for P in [True, False]:
for Q in [True, False]:
for R in [True, False]:
P_implies_Q = not P or Q
Q_implies_R = not Q or R
P_implies_Q_and_Q_implies_R = P_implies_Q and Q_implies_R
result = P_implies_Q_and_Q_implies_R <= (not P or R)
print('{}\t{}\t{}\t{}\t{}\t{}\t{}'.format(
P, Q, R, P_implies_Q, Q_implies_R, P_implies_Q_and_Q_implies_R, result))
```
你可以复制这段代码,粘贴到PyCharm中,运行后即可得到推理的有效性验证结果。如果所有情况下都能得到结论,则说明推理有效。