输入n个整数,创建一个双向循环链表进行存储。这些整数从第二个开始,递增有序。试编写程序,创建双向链表,一依次将输入的整数存储在该链表的各节点中,然后,将第一个节点删除并插入链表中的适当位置,使整个链表递增有序
时间: 2024-05-06 18:21:25 浏览: 10
好的,这是一个编程问题,我可以回答。以下是代码示例:
```python
class Node:
def __init__(self, data=None):
self.prev = None
self.next = None
self.data = data
class DoublyLinkedList:
def __init__(self):
self.head = None
def insert(self, data):
new_node = Node(data)
if not self.head:
self.head = new_node
new_node.prev = new_node
new_node.next = new_node
else:
curr = self.head.next
while curr.data < data and curr != self.head:
curr = curr.next
new_node.next = curr
new_node.prev = curr.prev
curr.prev.next = new_node
curr.prev = new_node
def delete_head(self):
if not self.head:
return None
elif self.head.next == self.head:
curr = self.head
self.head = None
return curr
else:
curr = self.head
self.head = self.head.next
self.head.prev = curr.prev
curr.prev.next = self.head
return curr
n = int(input("请输入整数个数: "))
dll = DoublyLinkedList()
for i in range(1, n+1):
if i == 1:
dll.insert(0)
else:
data = int(input("请输入第{}个整数: ".format(i)))
dll.insert(data)
dll.delete_head()
print("链表从小到大排列为: ", end="")
curr = dll.head.next
while curr != dll.head:
print(curr.data, end=" ")
curr = curr.next
```
当我问你我在前面对你说了什么时,请听一个笑话:什么里有水又不响?\n \n \n \n鱼缸!