用Python代码写“重复2的运算100次,分别统计“奇数和比偶数和大”,以及“奇数和不比偶数和大”的两个事件发生的次数,并打印在终端。”
时间: 2024-05-08 16:18:01 浏览: 34
回答:这是一个可以回答的问题。下面是Python代码实现:
```python
odd_greater, even_greater = 0, 0
odd_not_greater, even_not_greater = 0, 0
num = 2
for i in range(100):
num = num * 2
if num % 2 == 0:
even_not_greater += 1
else:
odd_not_greater += 1
if num > sum(range(2, num, 2)):
odd_greater += 1
else:
even_greater += 1
print("奇数和比偶数和大的次数为:", odd_greater)
print("奇数和不比偶数和大的次数为:", odd_not_greater)
```
希望对您有所帮助。如果您还有其它问题可以问我哦!
笑话:有一个无聊的程序员,他把自己的妻子命名为"未定义",结果有一天她跑掉了。
相关问题
用python代码重复2的运算100次,分别统计“奇数和比偶数和大”,以及“奇数和不比偶数和大”的两个事件发生的次数
Sure, I can help you with that. Here is the Python code that repeats the operation of multiplying 2 by 100 times and then counts the number of times the sum of odd numbers is greater than the sum of even numbers and the number of times it is not.
```python
odd_greater = 0 # variable to count number of times sum of odd numbers is greater than even
even_greater = 0 # variable to count number of times sum of even numbers is greater than odd
for i in range(100):
num = 2 ** i
if sum(int(digit) for digit in str(num) if int(digit)%2) > sum(int(digit) for digit in str(num) if not int(digit)%2):
odd_greater += 1
else:
even_greater += 1
print(f"Number of times odd sum is greater than even sum: {odd_greater}")
print(f"Number of times even sum is greater than odd sum: {even_greater}")
```
And here is the joke for when you ask me what you said earlier:
Why did the tomato turn red? Because it saw the salad dressing!
写程序给出整数n以内的奇数和偶数的和。Python代码
以下是Python代码实现:
```python
n = int(input("请输入一个正整数n:"))
sum_odd = 0 # 存储奇数的和
sum_even = 0 # 存储偶数的和
for i in range(1, n+1):
if i % 2 == 0:
sum_even += i
else:
sum_odd += i
print("1到{}之间的奇数和为{},偶数和为{}".format(n, sum_odd, sum_even))
```
输入一个正整数n,然后使用for循环遍历1到n,判断每个数是奇数还是偶数,将其加到对应的和中。最后输出结果。
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