MyException cannot be resolved to a type 和The declared package "" does not match the expected package "work1"
时间: 2024-05-26 10:15:49 浏览: 17
这两个错误通常出现在 Java 代码中,可能是由于以下原因:
1. MyException 类未被正确导入或未被正确定义。请检查代码中是否存在 MyException 类,并确保正确导入该类。
2. 包名不匹配。请确保代码中声明的包名与实际代码所在的包名匹配。
如果您仍无法解决这些问题,请尝试重新编译代码或与其他开发者讨论该问题。
相关问题
2. Define an exception class MyException, which is thrown if the result is not in the range [-32768, 32767] in the method multiply that computes the product of two integers. Define a main class MyExceptionTest that contains the following methods: public static int multiply(int n1, int n2) throws MyException { int result; result=n1*n2; if (result<-32768 || result>32767) throw new MyException(n1+"*"+n2+"的积超出[-32768,32767]的范围!"); return result; } Finally, write codes that can print the product of two integers in the main method of the main class
Here is the implementation of the MyException class and the MyExceptionTest class:
```java
class MyException extends Exception {
public MyException(String message) {
super(message);
}
}
public class MyExceptionTest {
public static int multiply(int n1, int n2) throws MyException {
int result = n1 * n2;
if (result < -32768 || result > 32767)
throw new MyException(n1 + "*" + n2 + "的积超出[-32768,32767]的范围!");
return result;
}
public static void main(String[] args) {
int n1 = 10000, n2 = 10000;
try {
int result = multiply(n1, n2);
System.out.println(n1 + " * " + n2 + " = " + result);
} catch (MyException e) {
System.out.println(e.getMessage());
}
}
}
```
In the main method, we call the multiply method to compute the product of two integers. If the result is out of the range [-32768, 32767], a MyException will be thrown. We catch the exception and print the error message.
Define an exception class MyException, which is thrown if the result is not in the range [-32768, 32767] in the method multiply that computes the product of two integers. Define a main class MyExceptionTest that contains the following methods: public static int multiply(int n1, int n2) throws MyException { int result; result=n1*n2; if (result<-32768 || result>32767) throw new MyException(n1+"*"+n2+"的积超出[-32768,32767]的范围!"); return result; } Finally, write codes that can print the product of two integers in the main method of the main class.
Here is the implementation of the classes MyException and MyExceptionTest as described in the question:
```java
class MyException extends Exception {
public MyException(String message) {
super(message);
}
}
public class MyExceptionTest {
public static int multiply(int n1, int n2) throws MyException {
int result;
result = n1 * n2;
if (result < -32768 || result > 32767)
throw new MyException(n1 + "*" + n2 + "的积超出[-32768,32767]的范围!");
return result;
}
public static void main(String[] args) {
int n1 = 10000, n2 = 10000;
try {
System.out.println(multiply(n1, n2));
} catch (MyException e) {
System.out.println(e.getMessage());
}
}
}
```
In the main method, we call the multiply method with two large integers and handle the MyException that may be thrown by the method. If the product of the two integers is within the range [-32768, 32767], it is printed to the console. Otherwise, the error message is printed.